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As the head of a social services agency, you believe that your staff of 20 social workers is very much overworked compared with 10 years ago. The case loads for each worker are reported below for each of the two years in question. Has the average caseload increased? Which measure of central tendency is most appropriate to answer this question? Why? \(\begin{array}{llll} \hline {2002} & & {2012} \\ \hline 52 & 55 & 42 & 82 \\ 50 & 49 & 75 & 50 \\ 57 & 50 & 69 & 52 \\ 49 & 52 & 65 & 50 \\ 45 & 59 & 58 & 55 \\ 65 & 60 & 64 & 65 \\ 60 & 65 & 69 & 60 \\ 55 & 68 & 60 & 60 \\ 42 & 60 & 50 & 60 \\ 50 & 42 & 60 & 60 \\ \hline \end{array}\)

Short Answer

Expert verified
The average caseload has increased. The mean is the most appropriate measure because it provides a comprehensive overview of the data.

Step by step solution

01

- Organize the Data

Organize the given caseload data for the years 2002 and 2012.
02

- Calculate the Mean for 2002

Calculate the mean (average) for the caseload of 2002. The mean is calculated by adding all the numbers and dividing by the total count of numbers: \( \text{Mean}_{2002} = \frac{52 + 50 + 57 + 49 + 45 + 65 + 60 + 55 + 42 + 50}{10} \).
03

- Calculate the Mean for 2012

Calculate the mean (average) for the caseload of 2012. The mean is calculated by adding all the numbers and dividing by the total count of numbers: \( \text{Mean}_{2012} = \frac{55 + 49 + 50 + 52 + 59 + 60 + 65 + 68 + 60 + 42}{10} \).
04

- Compare the Means

Compare the means of 2002 and 2012. The average caseload has increased if \( \text{Mean}_{2012} \) is greater than \( \text{Mean}_{2002} \).
05

- Determine the Appropriate Measure of Central Tendency

The mean is the most appropriate measure of central tendency for this question because it takes into account all data points and provides a single value that represents the overall caseload of the workers.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean Calculation
The mean, also known as the average, is a fundamental concept in statistics. It's used to find the central value of a data set. To calculate a mean, you sum up all the numbers in the data set, and then divide by the number of values.
For example, for the caseloads in 2002:
\[ \text{Mean}_{2002} = \frac{52 + 50 + 57 + 49 + 45 + 65 + 60 + 55 + 42 + 50}{10} = \frac{525}{10} = 52.5 \]
Similarly, for the caseloads in 2012:
\[ \text{Mean}_{2012} = \frac{55 + 49 + 50 + 52 + 59 + 60 + 65 + 68 + 60 + 42}{10} = \frac{560}{10} = 56.0 \] The mean gives us a clear picture of the central tendency of the caseload distribution for each year. By comparing these means, we can determine if the workload has increased or decreased over time.
Data Comparison
Once you've calculated the means for both years, the next step is to compare them. In our example, the mean caseload for 2002 was 52.5, and for 2012 it was 56.0. Since 56.0 is greater than 52.5, we can conclude that the average caseload has increased over the 10-year period.
It's crucial to compare means to see trends over time. This can help in identifying whether certain interventions or changes (like increased support or policy changes) might be necessary.
When comparing data:
  • Look for increases or decreases between the compared values.
  • Consider factors that might have influenced the changes.
  • Use clear metrics, like the mean, to make informed decisions.
Comparing the two means helps us understand the trend and make data-driven decisions about workload management.
Workload Assessment
Assessing workload is an important task for any organization. For social services agencies, understanding the caseload for each worker is vital in ensuring efficiency and avoiding burnout.
The increase in mean caseload from 2002 to 2012 indicates that social workers are handling more cases on average, suggesting an increase in overall workload. Regular assessment can help manage resource allocation and ensure workers are not overwhelmed.
Key steps in workload assessment include:
  • Regularly collecting data on the task loads of workers.
  • Computing the mean to identify central trends.
  • Comparing these trends over different time periods.
  • Implementing changes based on data insights to improve work conditions.
By continually monitoring and assessing the workload, agencies can take proactive steps to maintain a balanced and manageable distribution of tasks among their staff.

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Most popular questions from this chapter

Professional athletes are threatening to strike because they claim that they are underpaid. The team owners have released a statement that says, in part, "The average salary for players was $$\$ 1.2$$ million last year." The players counter by issuing their own statement that says, in part, "The typical player earned only $$\$ 753,000$$ last year." Is either side necessarily lying? If you were a sports reporter and had just read Chapter 3 of this text, what questions would you ask about these statistics?

You have compiled the following information on each of the graduates voted "most likely to succeed" by a local high school for a 10 -year period. For each variable, find the appropriate measure of central tendency. $$ \begin{array}{ccccc} \hline \hline & & & & \text { Years of } \\ & & & & \text { Education } \\ \text { Case } & \begin{array}{c} \text { Present } \\ \text { Income (\$) } \end{array} & \begin{array}{c} \text { Marital } \\ \text { Status } \end{array} & \begin{array}{c} \text { Owns a } \\ \text { Home? } \end{array} & \begin{array}{l} \text { Post-High } \\ \text { School } \end{array} \\ \hline \mathrm{A} & 104,000 & \text { Divorced } & \text { Yes } & 8 \\ \mathrm{~B} & 68,000 & \text { Divorced } & \text { No } & 4 \\ \mathrm{C} & 54,000 & \text { Married } & \text { Yes } & 4 \\ \mathrm{D} & 45,000 & \text { Married } & \text { No } & 4 \\ \mathrm{E} & 40,000 & \text { Single } & \text { No } & 4 \\ \mathrm{~F} & 85,000 & \text { Separated } & \text { Yes } & 8 \\ \mathrm{G} & 30,000 & \text { Married } & \text { No } & 3 \\ \mathrm{H} & 27,000 & \text { Married } & \text { No } & 1 \\ 1 & 93,000 & \text { Married } & \text { Yes } & 6 \\ \mathrm{~J} & 48,000 & \text { Single } & \text { Yes } & 4 \end{array} $$

A variety of information has been collected for all district high schools. Find the most appropriate measure of central tendency for each variable, and summarize this information in a paragraph. (HINT: The level of measurement of the variable will generally tell you which measure of central tendency is appropriate. Remember to organize the scores from high to low before finding the median.) $$\begin{array}{cclclc} \text { High School } & \text { Enrollment } & \begin{array}{c} \text { Largest Racial/ } \\ \text { Ethnic Group } \end{array} & \begin{array}{c} \% \text { College } \\ \text { Bound } \end{array} & \begin{array}{c} \text { Most Popular } \\ \text { Sport } \end{array} & \begin{array}{c} \text { Condition of } \\ \text { Physical Plant } \\ (10=\text { Excellent) } \end{array} \\ \hline \text { A } & 1400 & \text { White } & 25 & \text { Football } & 10 \\ \text { B } & 1223 & \text { White } & 77 & \text { Baseball } & 7 \\ \text { C } & 876 & \text { Black } & 52 & \text { Football } & 5 \\ \text { D } & 1567 & \text { Hispanic } & 29 & \text { Football } & 8 \\ \text { E } & 778 & \text { White } & 43 & \text { Basketball } & 4 \\ \text { F } & 1690 & \text { Black } & 35 & \text { Basketball } & 5 \\ \text { G } & 1250 & \text { White } & 66 & \text { Soccer } & 6 \\ \text { H } & 970 & \text { White } & 54 & \text { Football } & 9 \\ \hline \end{array}$$

A variety of information has been gathered from a sample of college freshmen and seniors, including \- Their region of birth; \- The extent to which they support legalization of marijuana (measured on a scale on which \(7=\) strong support, \(4=\) neutral, and \(1=\) strong opposition); \- The amount of money they spend each week outof-pocket for food, drinks, and entertainment; \- How many movies they watched in their dorm rooms last week; \- Their opinion of cafeteria food \((10=\) excellent, \(0=\) very bad ); and \- Their religious affiliation. Some results are presented here. Find the most appropriate measure of central tendency for each variable for freshmen and then for seniors. Report both the measure you selected and its value for each variable (e.g., "Mode \(=3\) " or "Median \(=3.5\) "). (HINT: Determine the level of measurement for each variable first. In general, this will tell you which measure of central tendency is appropriate. See the section "Choosing a Measure of Central Tendency" to review the relationship between measure of central tendency and level of measurement. Also, remember that the mode is the most common score, and especially remember to array scores from high to low before finding the median.) \(\begin{array}{clccccl} \hline \hline & & {\text { FRESHMEN }} & & & \\ \text { Student } & \text { Region of Birth } & \text { Legalization } & \text { Out-of- Pocket Expenses } & \text { Movies } & \text { Cafeteria Food } & \text { Religion } \\ \hline \text { A } & \text { North } & 7 & 43 & 0 & 10 & \text { Protestant } \\\ \text { B } & \text { North } & 4 & 49 & 14 & 7 & \text { Protestant } \\ \text { C } & \text { South } & 3 & 55 & 10 & 2 & \text { Catholic } \\ \text { D } & \text { Midwest } & 2 & 57 & 7 & 1 & \text { None } \\ \text { E } & \text { North } & 3 & 72 & 5 & 8 & \text { Protestant } \\ \text { F } & \text { North } & 5 & 58 & 1 & 6 & \text { Jew } \\ \text { G } & \text { South } & 1 & 62 & 0 & 10 & \text { Protestant } \\ \text { H } & \text { South } & 4 & 75 & 14 & 0 & \text { Other } \\ \text { I } & \text { Midwest } & 1 & 61 & 3 & 5 & \text { Other } \\ \text { J } & \text { West } & 2 & 53 & 4 & 6 & \text { Catholic } \\ \hline \end{array}\) \(\begin{array}{clccccl} \hline & {\text { SENIORS }} \\ \text { Student } & \text { Region of Birth } & \text { Legalization } & \text { Out-of- Pocket Expenses } & \text { Movies } & \text { Cafeteria Food } & \text { Religion } \\ \hline \mathrm{K} & \text { North } & 7 & 75 & 0 & 1 & \text { None } \\ \mathrm{L} & \text { Midwest } & 6 & 72 & 5 & 2 & \text { Protestant } \\ \mathrm{M} & \text { North } & 7 & 70 & 11 & 8 & \text { Protestant } \\ \mathrm{N} & \text { North } & 5 & 95 & 3 & 4 & \text { Catholic } \\ \mathrm{O} & \text { South } & 1 & 72 & 4 & 3 & \text { Protestant } \\ \mathrm{P} & \text { South } & 5 & 67 & 14 & 6 & \text { Protestant } \\ \mathrm{Q} & \text { West } & 6 & 50 & 0 & 2 & \text { Catholic } \\ \mathrm{R} & \text { West } & 7 & 59 & 7 & 9 & \text { None } \\ \mathrm{S} & \text { North } & 3 & 55 & 5 & 4 & \text { None } \\ \mathrm{T} & \text { West } & 5 & 95 & 3 & 7 & \text { Other } \\ \mathrm{U} & \text { North } & 4 & 88 & 5 & 4 & \text { None } \end{array}\)

The college administration is considering a total ban on student automobiles. You have conducted a poll on this issue of 20 fellow students and 20 of the neighbors who live around the campus and have calculated scores for your respondents. On the scale you used, a high score indicates strong opposition to the proposed ban. The scores are presented here for both groups. Calculate an appropriate measure of central tendency and compare the two groups in a sentence or two. \(\begin{array}{rrrr} \hline {\text { Students }} & & {\text { Neighbors }} \\ \hline 10 & 11 & 0 & 7 \\ 10 & 9 & 1 & 6 \\ 10 & 8 & 0 & 0 \\ 10 & 11 & 1 & 3 \\ 9 & 8 & 7 & 4 \\ 10 & 11 & 11 & 0 \\ 9 & 7 & 0 & 0 \\ 5 & 1 & 1 & 10 \\ 5 & 2 & 10 & 9 \\ 0 & 10 & 10 & 0 \\ \hline \end{array}\)

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