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For the test scores first presented in problem \(2.6\) and reproduced here, compute a median and mean for both the pretest and posttest. Interpret these statistics. $$ \begin{array}{ccc} \text { Case } & \text { Pretest } & \text { Posttest } \\ \hline \text { A } & 8 & 12 \\ \text { B } & 7 & 13 \\ \text { C } & 10 & 12 \\ \text { D } & 15 & 19 \\ \text { E } & 10 & 8 \\ \text { F } & 10 & 17 \\ \text { G } & 3 & 12 \\ \text { H } & 10 & 11 \\ \text { ? } & 5 & 7 \\ \text { J } & 15 & 12 \\ \text { K } & 13 & 20 \\ \text { L } & 4 & 5 \\ \text { M } & 10 & 15 \\ \text { N } & 8 & 11 \\ \text { O } & 12 & 20 \\ \hline \end{array} $$

Short Answer

Expert verified
The median pretest score is 10 and mean is 8.67. The median posttest score is 12 and mean is 12.93, indicating improvement.

Step by step solution

01

- Arrange the Pretest Scores

First, list all the pretest scores. The scores are: 8, 7, 10, 15, 10, 10, 3, 10, 5, 15, 13, 4, 10, 8, 12. Arrange them in ascending order: 3, 4, 5, 7, 8, 8, 10, 10, 10, 10, 12, 13, 15, 15.
02

- Find the Median of Pretest Scores

Since there are 15 scores, the median is the 8th value. The median pretest score is 10.
03

- Calculate the Mean of Pretest Scores

Sum all pretest scores: 3 + 4 + 5 + 7 + 8 + 8 + 10 + 10 + 10 + 10 + 12 + 13 + 15 + 15 = 130. Divide by 15: Mean = 130/15 ≈ 8.67.
04

- Arrange the Posttest Scores

List all posttest scores: 12, 13, 12, 19, 8, 17, 12, 11, 7, 12, 20, 5, 15, 11, 20. Arrange them in ascending order: 5, 7, 8, 11, 11, 12, 12, 12, 12, 13, 15, 17, 19, 20, 20.
05

- Find the Median of Posttest Scores

With 15 scores, the median is the 8th value. The median posttest score is 12.
06

- Calculate the Mean of the Posttest Scores

Sum all posttest scores: 5 + 7 + 8 + 11 + 11 + 12 + 12 + 12 + 12 + 13 + 15 + 17 + 19 + 20 + 20 = 194. Divide by 15: Mean = 194/15 ≈ 12.93.
07

- Interpret the Statistics

The median and mean for the pretest scores are both close to each other, indicating a fairly symmetric distribution around 10. For the posttest, the median is 12 and the mean is slightly higher at approximately 12.93, indicating a slight skew towards higher scores. Overall, both statistics suggest an improvement from pretest to posttest.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Median
The median is a key concept in descriptive statistics. It represents the middle value of a data set when arranged in ascending order. For example, in our pretest scores (3, 4, 5, 7, 8, 8, 10, 10, 10, 10, 12, 13, 15, 15), the median is the 8th value—which is 10. This middle value effectively splits the data set into two halves. The median is particularly useful as it is not affected by outliers or extreme values, providing a stable measure of central tendency. Similarly, for our posttest scores set, the median was calculated to be 12.
Mean
The mean, another measure of central tendency, is the average of all the data points. To find the mean, sum up all the values in the data set and then divide by the number of values. For the pretest scores, the sum is 130, and dividing by the number of scores (15) gives a mean of approximately 8.67. For posttest scores, the sum is 194, with the same number of scores, resulting in a mean of approximately 12.93. Unlike the median, the mean can be influenced by outliers. It provides a general overview of the dataset but can be skewed by extremely high or low values.
Pretest Scores
Pretest scores are the results collected before an intervention or treatment is applied. In our exercise, we collected 15 pretest scores to establish a baseline for comparison. These scores ranged from 3 to 15. By analyzing pretest scores, we can assess the initial level of performance or understanding of the students. Calculating measures like median and mean helps us summarize this baseline data. This summary can then be used to make comparisons with posttest scores to evaluate any changes or improvements.
Posttest Scores
Posttest scores are the results gathered after a certain intervention or teaching method has been applied. For the examples given, we measured 15 posttest scores. These ranged from 5 to 20, indicating performance after the intervention. To summarize the effectiveness of the intervention, we can compare the posttest scores to the pretest scores. This comparison helps determine if there has been an improvement. Calculations of the median (12) and mean (approximately 12.93) in the posttest scores offer insights into the overall improvement and distribution of scores.
Statistical Interpretation
Statistical interpretation involves making sense of the calculated statistics to draw meaningful conclusions. For this exercise, comparing the pretest and posttest scores provides insight into student progress. The median for pretest scores was 10, and for posttest scores, it was 12, suggesting a general improvement. The mean increased from approximately 8.67 (pretest) to 12.93 (posttest), also indicating improvement. The slight difference between median and mean in posttest results suggests a minor skew towards higher scores. Overall, these statistics collectively show a positive outcome from the intervention, indicating an improvement in student performance.

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Most popular questions from this chapter

A variety of information has been gathered from a sample of college freshmen and seniors, including their region of birth; the extent to which they support legalization of marijuana (measured on a scale on which \(7=\) strong support, \(4=\) neutral, and \(1=\) strong opposition); the amount of money they spend each week out-of-pocket for food, drinks, and entertainment; how many movies they watched in their dorm rooms last week; their opinion of cafeteria food \((10=\) excellent, \(0=\) very bad \()\); and their religious affiliation. Some results are presented here. Find the most appropriate measure of central tendency for each variable for freshmen and then for seniors. Report both the measure you selected as well as its value for each variable (e.g., "Mode \(=3\) " or "Median \(=3.5\) "). (HINT: Determine the level of measurement for each variable first. In general, this will tell you which measure of central tendency is appropriate. See the section "Choosing a Measure of Central Tendency" to review the relationship between measure of central tendency and level of measurement. Also, remember that the mode is the most common score, and especially remember to array scores from high to low before finding the median.) $$\text { Fresh Men}$$ \(\begin{array}{clccccl} \text { Student } & \text { Region of Birth } & \text { Legalization } & \text {Out-ofPocket Expenses } & \text { Movies } & \text { Food } & \text { Religion } \\ \hline \text { A } & \text { North } & 7 & 33 & 0 & 10 & \text { Protestant } \\\ \text { B } & \text { North } & 4 & 39 & 14 & 7 & \text { Protestant } \\ \text { C } & \text { South } & 3 & 45 & 10 & 2 & \text { Catholic } \\ \text { D } & \text { Midwest } & 2 & 47 & 7 & 1 & \text { None } \\ \text { E } & \text { North } & 3 & 62 & 5 & 8 & \text { Protestant } \\ \text { F } & \text { North } & 5 & 48 & 1 & 6 & \text { Jew } \\ \text { G } & \text { South } & 1 & 52 & 0 & 10 & \text { Protestant } \\ \text { H } & \text { South } & 4 & 65 & 14 & 0 & \text { Other } \\ \text { ? } & \text { Midwest } & 1 & 51 & 3 & 5 & \text { Other } \\ \text { J } & \text { West } & 2 & 43 & 4 & 6 & \text { Catholic } \end{array}\) \(\text { SENIORS }\) \(\begin{array}{clccccl} \text { Student } & \text {Region of Birth } & \text { Legalization } & \text {Out-ofPocket Expenses } & \text { Movies } & \text { Cafeteria Food } & \text { Religion } \\ \hline \mathrm{K} & \text { North } & 7 & 65 & 0 & 1 & \text { None } \\ \mathrm{L} & \text { Midwest } & 6 & 62 & 5 & 2 & \text { Protestant } \\ \mathrm{M} & \text { North } & 7 & 60 & 11 & 8 & \text { Protestant } \\ \mathrm{N} & \text { North } & 5 & 90 & 3 & 4 & \text { Catholic } \\ \mathrm{O} & \text { South } & 1 & 62 & 4 & 3 & \text { Protestant } \\ \mathrm{P} & \text { South } & 5 & 57 & 14 & 6 & \text { Protestant } \\ \mathrm{Q} & \text { West } & 6 & 40 & 0 & 2 & \text { Catholic } \\ \mathrm{R} & \text { West } & 7 & 49 & 7 & 9 & \text { None } \\ \mathrm{S} & \text { North } & 3 & 45 & 5 & 4 & \text { None } \\ \mathrm{T} & \text { West } & 5 & 85 & 3 & 7 & \text { Other } \\ \mathrm{U} & \text { North } & 4 & 78 & 5 & 4 & \text { None } \end{array}\)

The administration is considering a total ban on student automobiles. You have conducted a poll on this issue of 20 fellow students and 20 of the neighbors who live around the campus and have calculated scores for your respondents. On the scale you used, a high score indicates strong opposition to the proposed ban. The scores are presented here for both groups. Calculate an appropriate measure of central tendency and compare the two groups in a sentence or two. $$\begin{array}{crcc} {\text { Students }} & & {\text { Neighbors }} \\ \hline 10 & 11 & 0 & 7 \\ 10 & 9 & 1 & 6 \\ 10 & 8 & 0 & 0 \\ 10 & 11 & 1 & 2 \\ 9 & 8 & 7 & 4 \\ 10 & 11 & 11 & 0 \\ 9 & 7 & 0 & 0 \\ 5 & 1 & 1 & 10 \\ 5 & 2 & 10 & 9 \\ 0 & 10 & 10 & 0 \end{array}$$

A variety of information has been collected for all district high schools. Find the most appropriate measure of central tendency for each variable and summarize this information in a paragraph. (HINT: The level of measurement of the variable will generally tell you which measure of central tendency is appropriate. Remember to organize the scores from high to low before finding the median.) $$\begin{array}{cccccc} \text {High School } & \text { Enrollment } & \text {Largest Racial/ Ethnic Group } & \text {Percent College Bound } & \text {Most Popular Sport } & \text {Condition of Physical Plant (scale of \(1-10\) with } 10 \text { high }) \\ \hline 1 & 1400 & \text { White } & 25 & \text { Football } & 10 \\ 2 & 1223 & \text { White } & 77 & \text { Baseball } & 7 \\ 3 & 876 & \text { Black } & 52 & \text { Football } & 5 \\ 4 & 1567 & \text { Hispanic } & 29 & \text { Football } & 8 \\ 5 & 778 & \text { White } & 43 & \text { Basketball } & 4 \\ 6 & 1690 & \text { Black } & 35 & \text { Basketball } & 5 \\ 7 & 1250 & \text { White } & 66 & \text { Soccer } & 6 \\ 8 & 970 & \text { White } & 54 & \text { Football } & 9 \end{array}$$

The following table presents the annual personhours of time lost due to traffic congestion for a group of cities for 2007. This statistic is a measure of traffic congestion $$\begin{array}{lc} {\text { City }} & \text { Annual Person-Hours of Time Lost to Traffic Congestion per Year per Person } \\ \hline \text { Baltimore } & 25 \\ \text { Boston } & 22 \\ \text { Buffalo } & 5 \\ \text { Chicago } & 22 \\ \text { Cleveland } & 7 \\ \text { Dallas } & 32 \\ \text { Detroit } & 29 \\ \text { Houston } & 32 \\ \text { Kansas City } & 8 \\ \text { Los Angeles } & 38 \\ \text { Miami } & 27 \\ \text { Minneapolis } & 22 \\ \text { New Orleans } & 10 \\ \text { New York } & 21 \\ \text { Philadelphia } & 21 \\ \text { Pittsburgh } & 8 \\ \text { Phoenix } & 23 \\ \text { San Antonio } & 21 \\ \text { San Diego } & 29 \\ \text { San Francisco } & 29 \\ \text { Seattle } & 24 \\ \text { Washington, DC } & 31 \end{array}$$ a. Calculate the mean and median of this distribution. b. Compare the mean and median. Which is the higher value? Why? c. If you removed Los Angeles from this distribution and recalculated, what would happen to the mean? To the median? Why? d. Report the mean and median as you would in a formal research report.

Professional athletes are threatening to strike because they claim that they are underpaid. The team owners have released a statement that says, in part, "The average salary for players was $$\$ 1.2$$ million last year." The players counter by issuing their own statement that says, in part, "The average player earned only $$\$ 753,000$$ last year." Is either side necessarily lying? If you were a sports reporter and had just read Chapter 3 of this text, what questions would you ask about these statistics?

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