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To solve problems involving projectiles traveling through the air by applying the law of conservation of momentum requires evaluating the momentum of the system immediately before and immediately after the collision or explosion. Why?

Short Answer

Expert verified
#Short_Answer# Solving problems involving projectiles traveling through the air requires applying the law of conservation of momentum because it helps us determine the effect of collisions or explosions on the projectile's motion. By analyzing the momentum immediately before and after these events, we can calculate the changes in velocities and masses, allowing us to examine the modified horizontal and vertical motion of the projectile and ultimately solve the problem.

Step by step solution

01

Understand the problem

We are given a projectile problem, which typically involves an object being thrown or launched in the air. The motion of the projectile can be affected by factors such as collisions or explosions. Our goal is to understand why analyzing the momentum before and after these events is crucial for solving problems involving projectiles.
02

Explain conservation of momentum

The law of conservation of momentum states that the total momentum of a closed system (one that does not experience external forces) remains constant. In the case of projectile motion, we can apply this law to analyze the momentum of the projectile immediately before and after a collision or explosion.
03

Break down the projectile motion problem

To solve a projectile motion problem, we need to analyze two main components: the horizontal and vertical motion of the object. These components are independent of each other. - Horizontal motion: The horizontal speed of the projectile is constant (assuming no air resistance). Hence, the horizontal momentum, given by the product of the object's mass and horizontal velocity, also remains constant. - Vertical motion: The vertical motion is affected by gravity, which causes the object to accelerate downwards. Thus, the vertical velocity of the projectile changes during the motion.
04

Apply conservation of momentum to collisions and explosions

When a projectile experiences a collision or explosion, the law of conservation of momentum helps us determine the new motion of the projectile. - Immediately before a collision or explosion, the total momentum of the projectile can be calculated by considering both its horizontal and vertical motion. - Immediately after the event, the new momentum can be calculated by accounting for the changes in velocities and masses due to the collision or explosion.
05

Relate the conservation of momentum to solving projectile problems

By evaluating the momentum of the projectile immediately before and after the collision or explosion, we can determine the effect of these events on the overall motion of the projectile. By conserving the total momentum, we can find the new velocities and masses, which will subsequently enable us to analyze the modified horizontal and vertical motion of the projectile and solve the problem.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Projectile Motion Analysis
When we talk about projectile motion analysis, we are referring to the study of objects launched into the air and the forces acting upon them. This includes the initial launch at a certain angle and velocity, the path the projectile takes, and its final position when it lands or hits a target. To fully understand projectile motion, we break it down into its horizontal and vertical components.

For projectiles, we usually assume that the only force acting on them once they are in the air is gravity (neglecting air resistance). This means that the motion of a projectile is a combination of constant horizontal velocity and uniformly accelerated vertical motion due to gravity. By using equations for linear motion, one can predict the future position and velocity of the projectile at any point in time. Analysis often involves calculating the maximum height, the time of flight, and the range of the projectile.
Law of Conservation of Momentum
The law of conservation of momentum is a fundamental principle in physics which states that if no external forces are acting on a system, the total momentum of that system remains constant over time. Momentum, a vector quantity, is defined as the product of an object's mass and velocity. In other words, if two objects collide or separate from an explosion within a system with no external influence, the sum of their momenta before the event will equal the sum of their momenta after the event.

This law is extensively applied in projectile motion to understand events like collisions or explosions affecting a projectile's path. For example, when a firework explodes midair, the total momentum of all fragments combined right after the explosion is equal to the momentum of the firework just before it exploded. The importance in identifying momentum before and after an event lies in the ability to predict the resultant velocities and directions of the projectile or its fragments.
Collision and Explosion Dynamics
In collision and explosion dynamics, we are dealing with the interaction between two or more objects that exert forces on each other for a very short time period, resulting in a change of their velocities. These dynamics are governed by the laws of motion and the conservation of momentum. During a collision, objects may stick together, bounce off one another, or deform, and each scenario has different outcomes in terms of energy and momentum.

Types of Collisions

  • Elastic Collision: Both momentum and kinetic energy are conserved. The objects bounce off each other without a permanent deformation.
  • Inelastic Collision: Momentum is conserved but kinetic energy is not. Objects may stick together or deform, losing kinetic energy usually in the form of heat.
Explosions involve a single object breaking into multiple pieces due to some internal force or reaction. Momentum is conserved, but the kinetic energy changes – it generally increases as the internal energy stored within the object is converted to kinetic energy of the fragments.
Horizontal and Vertical Components of Motion
Every projectile motion can be dissected into its horizontal and vertical components of motion. These two components are independent of each other - meaning the vertical motion does not affect the horizontal motion and vice versa. The reason for this independence lies in the fact that different forces govern each motion. The horizontal motion is governed solely by the initial launch speed and the absence of horizontal forces (assuming no air resistance), resulting in a constant velocity. In contrast, the vertical motion is affected by gravity, which acts downwards, causing the motion to be uniformly accelerated.

Horizontal Motion:

Since no forces act horizontally, the horizontal component of a projectile's velocity remains unchanged throughout its flight, and thus its momentum in the horizontal direction is conserved.

Vertical Motion:

The vertical motion starts at an initial velocity (which can be zero) and changes due to the constant acceleration of gravity. At the highest point of its trajectory, the vertical velocity is zero, after which the projectile begins to fall back down, increasing its downward velocity until it impacts the ground or an object.

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Most popular questions from this chapter

Which of the following statements about car collisions is (are) true? a) The essential safety benefit of crumple zones (parts of the front of a car designed to receive maximum deformation during a head-on collision) is due to their absorbing kinetic energy, converting it into deformation, and lengthening the effective collision time, thus reducing the average force experienced by the driver. b) If car 1 has mass \(m\) and speed \(v,\) and car 2 has mass \(0.5 m\) and speed \(1.5 v\), then both cars have the same momentum. c) If two identical cars with identical speeds collide head on, the magnitude of the impulse received by each car and each driver is the same as if one car at the same speed had collided head on with a concrete wall. d) Car 1 has mass \(m,\) and car 2 has mass \(2 m .\) In a head-on collision of these cars while moving at identical speeds in opposite directions, car 1 experiences a bigger acceleration than car 2 . e) Car 1 has mass \(m,\) and car 2 has mass \(2 m .\) In a head-on collision of these cars while moving at identical speeds in opposite directions, car 1 receives an impulse of bigger magnitude than that received by car 2 .

The nucleus of radioactive thorium -228 , with a mass of about \(3.78 \cdot 10^{-25} \mathrm{~kg},\) is known to decay by emitting an alpha particle with a mass of about \(6.64 \cdot 10^{-27} \mathrm{~kg} .\) If the alpha particle is emitted with a speed of \(1.80 \cdot 10^{7} \mathrm{~m} / \mathrm{s}\), what is the recoil speed of the remaining nucleus (which is the nucleus of a radon atom)?

A 60.0 -kg astronaut inside a 7.00 -m-long space capsule of mass \(500 . \mathrm{kg}\) is floating weightlessly on one end of the capsule. He kicks off the wall at a velocity of \(3.50 \mathrm{~m} / \mathrm{s}\) toward the other end of the capsule. How long does it take the astronaut to reach the far wall?

A particle \(\left(M_{1}=1.00 \mathrm{~kg}\right)\) moving at \(30.0^{\circ}\) downward from the horizontal with \(v_{1}=2.50 \mathrm{~m} / \mathrm{s}\) hits a second particle \(\left(M_{2}=2.00 \mathrm{~kg}\right)\) which is at rest. After the collision, the speed of \(M_{1}\) is reduced to \(0.500 \mathrm{~m} / \mathrm{s},\) and it is moving to the left and at an angle of \(32.0^{\circ}\) downward withrespect to the horizontal. You cannot assume that the collision is elastic. What is the speed of \(M_{2}\) after the collision?

Two gliders are moving on a horizontal frictionless air track. Glider 1 is moving to the right (positive \(x\) -direction) with a speed of \(2.277 \mathrm{~m} / \mathrm{s}\). Glider 2 has mass \(m_{2}=277.3 \mathrm{~g}\) and is moving to the left (negative \(x\) -direction ) with a speed of \(3.789 \mathrm{~m} / \mathrm{s}\). The gliders undergo a totally elastic collision. The velocity of glider 1 after the collision is \(-4.887 \mathrm{~m} / \mathrm{s}\). What is the mass of glider \(1 ?\)

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