Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Consider a ballistic pendulum (see Section 7.6 ) in which a bullet strikes a block of wood. The wooden block is hanging from the ceiling and swings up to a maximum height after the bullet strikes it. Typically, the bullet becomes embedded in the block. Given the same bullet, the same initial bullet speed, and the same block, would the maximum height of the block change if the bullet did not get stopped by the block but passed through to the other side? Would the height change if the bullet and its speed were the same but the block was steel and the bullet bounced off it, directly backward?

Short Answer

Expert verified
Answer: Scenario 2, where the block is made of steel and the bullet bounces off, results in the same maximum height as in the initial situation. This is because both momentum and kinetic energy are conserved in this elastic collision, and the maximum height will not be affected if the bullet's speed and mass remain the same.

Step by step solution

01

Understand the initial scenario

Initially, the bullet is moving horizontally with a certain initial speed while the block is hanging from the ceiling at rest.
02

Determine the maximum height

We need to find the maximum height the combined bullet-block system reaches after the collision. To do this, we will use the conservation of momentum and energy in each scenario.
03

Scenario 1 - Bullet passes through the block

In this case, the bullet exchanges some of its momentum with the block but does not become embedded in it. We analyze this situation using the conservation of momentum: m_bullet * v_bullet_initial = (m_bullet + m_block) * v_system_final Since the total mechanical energy is not conserved in this inelastic collision, we cannot conclude if the maximum height would be the same as in the initial scenario.
04

Scenario 2 - Steel block and bullet bounce off

Now, when the block is made of steel, the bullet bounces off instead of getting embedded. This situation can be considered an elastic collision, so both momentum and kinetic energy are conserved: m_bullet * v_bullet_initial = m_bullet * (-v_bullet_final) + m_block * v_block_final Given that both momentum and kinetic energy are the same as in the initial scenario, we can conclude that the maximum height will not be affected if the bullet's speed and mass remain the same.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conservation of Momentum
The principle of conservation of momentum tells us that when no external forces act on a system, the total momentum of that system remains constant. Momentum is a vector quantity, defined as the product of an object's mass and its velocity (\( p = mv \)). In a physics problem involving a collision, such as the one with the ballistic pendulum, understanding this principle is crucial.

When a bullet strikes a block, as described in the exercise, the bullet and block together constitute an isolated system, assuming no external forces are acting on it (like air resistance or additional external forces). Therefore, the momentum before and after the collision must be the same.

Understanding conservation of momentum allows us to set up equations to solve for unknowns such as the final velocity of the system after the collision (\( m_{bullet} \times v_{bullet_{initial}} = (m_{bullet} + m_{block}) \times v_{system_{final}} \text{). This concept is vital for predicting the outcomes of collision events in physics.
Inelastic Collision
An inelastic collision is characterized by the merging or joint movement of colliding objects after the impact. In these scenarios, kinetic energy is not conserved, although momentum is. This aspect is crucial to understand the situation where the bullet becomes embedded in the block of wood.

During this inelastic collision, the kinetic energy transforms into other forms of energy, such as internal energy or sound. This means that while we can use the conservation of momentum to find the final velocity of the system, we cannot directly use the conservation of kinetic energy to predict the height the block will reach thereafter.

The lack of kinetic energy conservation makes calculating the maximum height more complex, requiring further analysis of energy transformation during and after the collision.
Elastic Collision
In contrast to inelastic collisions, an elastic collision is an event where both momentum and kinetic energy are conserved. This conservation makes elastic collisions relatively simpler to analyze mathematically.

In the scenario where the bullet bounces off a steel block, we're dealing with an elastic collision. Both objects remain separate after the collision, and the kinetic energy remains within the system. Here, we can set up equations that reflect the conservation of kinetic energy in addition to momentum:
  • Momentum conservation equation: \( m_{bullet} \times v_{bullet_{initial}} = m_{bullet} \times (-v_{bullet_{final}}) + m_{block} \times v_{block_{final}} \)
  • Kinetic energy conservation equation: \( \frac{1}{2}m_{bullet}v_{bullet_{initial}}^2 = \frac{1}{2}m_{bullet}v_{bullet_{final}}^2 + \frac{1}{2}m_{block}v_{block_{final}}^2 \)
By solving these equations, we can affirm that the block's max height will not change if the bullet's mass and speed do not change, because the system's total mechanical energy is conserved before and after the collision.
Kinetic Energy Conservation
Kinetic energy conservation is a fundamental concept in physics that applies to certain types of collisions — specifically elastic collisions. Kinetic energy, expressed as \( \frac{1}{2}mv^2 \), represents the energy an object has due to its motion.

In our exercise, we're asked to consider whether the maximum height of a swinging block changes under different collision conditions. If kinetic energy is conserved (as in the case of an elastic collision), then the total mechanical energy of the system (potential energy and kinetic energy) before and after the collision should remain the same.

This conservation principle enables us to assert that the maximum height reached by the pendulum, which depends on the potential energy at that height, will not change if the initial kinetic energy remains the same. However, in inelastic collisions, where kinetic energy is not conserved, this direct conclusion cannot be made.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A Super Ball has a coefficient of restitution of 0.8887 . If the ball is dropped from a height of \(3.853 \mathrm{~m}\) above the floor, what maximum height will it reach on its third bounce?

In bocce, the object of the game is to get your balls (each with mass \(M=1.00 \mathrm{~kg}\) ) as close as possible to the small white ball (the pallina, mass \(m=0.0450 \mathrm{~kg}\) ). Your first throw positioned your ball \(2.00 \mathrm{~m}\) to the left of the pallina. If your next throw arrives with a speed of \(v=1.00 \mathrm{~m} / \mathrm{s}\) and the coefficient of kinetic friction is \(\mu_{\mathrm{k}}=0.200\), what are the final distances of your two balls from the pallina in each of the following cases? Assume that collisions are elastic. a) You throw your ball from the left, hitting your first ball. b) You throw your ball from the right, hitting the pallina.

A golf ball of mass 45.0 g moving at a speed of \(120 . \mathrm{km} / \mathrm{h}\) collides head on with a French TGV high-speed train of mass \(3.80 \cdot 10^{5} \mathrm{~kg}\) that is traveling at \(300 . \mathrm{km} / \mathrm{h}\). Assuming that the collision is elastic, what is the speed of the golf ball after the collision? (Do not try to conduct this experiment!)

A ball with mass \(3.00 \mathrm{~kg}\) falls straight down onto a \(45^{\circ}\) -wedge that is rigidly attached to the ground. The ball is moving a speed of \(4.50 \mathrm{~m} / \mathrm{s}\) when it strikes the wedge. Assuming that the collision is instantaneous and perfectly elastic, what is the recoil momentum that the Earth receives during this collision?

Two gliders are moving on a horizontal frictionless air track. Glider 1 has mass \(m_{1}=160.1 \mathrm{~g}\) and is moving to the right (positive \(x\) -direction) with a speed of \(2.723 \mathrm{~m} / \mathrm{s}\). Glider 2 has mass \(m_{2}=354.1 \mathrm{~g}\) and is moving to the left (negative \(x\) -direction) with a speed of \(3.515 \mathrm{~m} / \mathrm{s}\). The gliders undergo a totally elastic collision. What is the velocity of glider 1 after the collision?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free