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A car of mass \(987 \mathrm{~kg}\) is traveling on a horizontal segment of a freeway with a speed of 64.5 mph. Suddenly, the driver has to hit the brakes hard to try to avoid an accident up ahead. The car does not have an ABS (antilock braking system), and the wheels lock, causing the car to slide some distance before it is brought to a stop by the friction force between its tires and the road surface. The coefficient of kinetic friction is \(0.301 .\) How much mechanical energy is lost to heat in this process?

Short Answer

Expert verified
Answer: The mechanical energy lost to heat in this process is 399,843.5 Joules.

Step by step solution

01

1. Convert speed from mph to m/s

We need to convert the speed of the car from miles per hour (mph) to meters per second (m/s). To do this, we can use the following conversion factors: 1 mile = 1,609.34 meters 1 hour = 3,600 seconds So, the conversion factor from mph to m/s is: 1 mph = (1,609.34 m / 1 mile) × (1 hour / 3,600 s) Now, we can convert the speed of the car: Speed (m/s) = 64.5 mph × 1.60934 km/mile × (1000 m/km) / 3600 s/hour Speed (m/s) = 28.8 m/s
02

2. Calculate the initial kinetic energy

The kinetic energy (KE) of the car can be calculated using the formula: KE = (1/2) m v^2 where m is the mass of the car (987 kg) and v is its speed (28.8 m/s). KE = (1/2) × 987 kg × (28.8 m/s)^2 KE = 399,843.5 J (Joules)
03

3. Calculate the work done by friction force

To calculate the work done by friction force to stop the car, we can use the formula: W = μ × m × g × d where W is the work done, µ is the coefficient of kinetic friction (0.301), m is the mass of the car (987 kg), g is the acceleration due to gravity (9.8 m/s²), and d is the distance the car slides to stop. First, we need to find the distance (d) the car slides. The work-energy principle states that the work done on an object equals the change in its kinetic energy. So, the work done by friction to stop the car is equal to the initial kinetic energy: W = 399,843.5 J Now, we can solve for the distance (d): d = W / (μ × m × g) d = 399,843.5 J / (0.301 × 987 kg × 9.8 m/s²) d = 139.5 m
04

4. Find the mechanical energy lost to heat

The mechanical energy lost to heat is equal to the work done by friction: Mechanical energy lost to heat = Work done by friction Mechanical energy lost to heat = 399,843.5 J Therefore, the mechanical energy lost to heat in this process is 399,843.5 Joules.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy
Kinetic energy represents the energy that an object possesses due to its motion. It is a form of energy that can be calculated for any moving object, from subatomic particles to large celestial bodies. When we talk about a moving car, like in our exercise, the kinetic energy is a crucial concept.

To calculate kinetic energy (\textbf{KE}), we use the formula \[\begin{equation}KE = \frac{1}{2}mv^2\text{,}\end{equation}\]where \[\begin{equation}m\end{equation}\]is the object's mass and \[\begin{equation}v\end{equation}\]is its velocity. In terms of units, kinetic energy is measured in Joules (J). For our example, the car's kinetic energy before it stops is equivalent to the work that must be done by the friction force to bring the car to rest—a force which in this case turns mechanical energy into heat.
Coefficient of Kinetic Friction
The coefficient of kinetic friction, denoted as \[\begin{equation}\mu\end{equation}\], is a dimensionless factor that describes the friction between two surfaces in relative motion. It is a measure of how easily one surface slides over another and determines the force of friction relative to the normal force (the force perpendicular to the contact surface).

Given a particular pair of surfaces, the coefficient of kinetic friction is generally a constant value under similar conditions. In the scenario of our car, the coefficient of kinetic friction between the locked tires and the road surface is given as 0.301. This value is used to calculate the work done by friction force and consequently, the mechanical energy transformation during the car's deceleration. It's essential to understand that the coefficient of kinetic friction plays a pivotal role in determining the deceleration rate and the distance over which the car slides.
Work-Energy Principle
The work-energy principle is a fundamental concept in classical mechanics, stating that the work done by all forces acting on an object will result in an equal change in the object's kinetic energy. This principle bridges the gap between force (work) and energy, allowing us to analyze various mechanical problems efficiently.

Mathematically, if the only significant force doing work is due to friction, such as in our textbook problem, the work (\[\begin{equation}W\end{equation}\]) done by friction force is the negative of the change in kinetic energy, because the kinetic energy decreases as the object comes to a stop. The calculation of work done by friction, therefore, can be found using the kinetic energy calculated before and after the event, which leads to the equation \[\begin{equation}W = \mu \times m \times g \times d\end{equation}\]. When applied, this principle tells us precisely how much mechanical energy has been transformed into heat due to the sliding friction between the car's tires and the road.

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Most popular questions from this chapter

A baseball is dropped from the top of a building. Air resistance acts on the baseball as it drops. Which of the following statements is true? a) The change in potential energy of the baseball as it falls is equal to the kinetic energy of the baseball just before it strikes the ground. b) The change in potential energy of the baseball as it falls is greater than the kinetic energy of the baseball just before it strikes the ground. c) The change in potential energy of the baseball as it falls is less than the kinetic energy of the baseball just before it strikes the ground. d) The change in potential energy of the baseball is equal to the energy lost due to the friction from the air resistance while the ball is falling.

A uniform chain of total mass \(m\) is laid out straight on a frictionless table and held stationary so that one-third of its length, \(L=1.00 \mathrm{~m}\), is hanging vertically over the edge of the table. The chain is then released. Determine the speed of the chain at the instant when only one-third of its length remains on the table.

How much work do you do when you hold a bag of groceries while standing still? How much work do you do when carrying the same bag a distance \(d\) across the parking lot of the grocery store?

Bolo, the human cannonball, is ejected from a 3.50 -m long barrel. If Bolo \((m=80.0 \mathrm{~kg})\) has a speed of \(12.0 \mathrm{~m} / \mathrm{s}\) at the top of his trajectory, \(15.0 \mathrm{~m}\) above the ground, what was the average force exerted on him while in the barrel?

A block of mass 5.0 kg slides without friction at a speed of \(8.0 \mathrm{~m} / \mathrm{s}\) on a horizontal table surface until it strikes and sticks to a horizontal spring (with spring constant of \(k=2000 . \mathrm{N} / \mathrm{m}\) and very small mass \(),\) which in turn is attached to a wall. How far is the spring compressed before the mass comes to rest? a) \(0.40 \mathrm{~m}\) c) \(0.30 \mathrm{~m}\) e) \(0.67 \mathrm{~m}\) b) \(0.54 \mathrm{~m}\) d) \(0.020 \mathrm{~m}\)

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