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An engine expends 40.0 hp in moving a car along a level track at a speed of \(15.0 \mathrm{~m} / \mathrm{s} .\) How large is the total force acting on the car in the direction opposite to the motion of the car?

Short Answer

Expert verified
Answer: The total force acting on the car in the direction opposite to its motion is approximately 1,989.33 N.

Step by step solution

01

Convert horsepower to watts

First, we need to convert the engine power from horsepower to watts. 1 hp is equal to 746 watts. So, 40 hp can be converted to watts by multiplying it with the conversion factor: $$40.0 \ \text{hp} \times \frac{746 \ \text{watts}}{1 \ \text{hp}} = 29,840 \ \text{watts}$$
02

Use the power formula

The formula for power is: $$\text{Power} = \text{Force} \times \text{Velocity}$$ We need to find the force acting on the car, so we can rearrange the formula to solve for Force: $$\text{Force} = \frac{\text{Power}}{\text{Velocity}}$$
03

Substitute the given values

Now, we can substitute the given values into the formula: $$\text{Force} = \frac{29,840 \ \text{watts}}{15.0 \ \text{m/s}}$$
04

Calculate the force

By dividing the power by the velocity, we can find the force acting on the car: $$\text{Force} = \frac{29,840}{15} \approx 1,989.33 \ \text{N}$$ So, the total force acting on the car in the direction opposite to the motion is approximately 1,989.33 N.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power to Force Calculation
Understanding the relationship between power and force is an essential aspect of physics problem-solving, particularly when analyzing mechanical systems like engines and vehicles. Power, in a physical context, refers to the rate at which work is done or energy is transferred. It is represented in watts (W) in the International System of Units (SI). When we relate power to force, we're essentially determining how much force is exerted over a certain distance within a specific timeframe.

To extract force from power, you need to know the velocity at which the object is moving. The formula tied to this concept is: \[\[\begin{align*}\text{Power} &= \text{Force} \times \text{Velocity}\end{align*}\]\]. By rearranging the formula to solve for Force, it becomes: \[\[\begin{align*}\text{Force} &= \frac{\text{Power}}{\text{Velocity}}\end{align*}\]\]. This rearrangement isolates the force as the subject of the equation, enabling us to determine how much force is responsible for the power output presented.
Horsepower to Watts Conversion
In many real-world applications, especially those related to automotive and mechanical engineering, power is commonly measured in horsepower (hp). One horsepower is the amount of energy it takes to lift 550 pounds one foot in one second and is equal to approximately 746 watts. The conversion from horsepower to watts is straightforward:

\[\[\begin{align*}\text{Watts} &= \text{Horsepower} \times 746\end{align*}\]\]. For instance, converting 40 horsepower to watts involves multiplying 40 by 746, yielding 29,840 watts. This conversion is crucial when you're working with power specifications not provided in the standard SI unit of watts. It's essential to operate within a common unit to apply the physical formulas correctly for problem-solving.
Force and Motion Analysis
The analysis of force and motion is a cornerstone of classical mechanics. Newton's second law of motion is foundational here, describing how the acceleration of an object is directly proportional to the net force acting upon it and inversely proportional to its mass. Fundamentally, force is what causes an object to accelerate, slow down, or continue moving at a constant speed despite resistance, such as friction.

Within the context of the exercise provided, the total force acting on the car in the direction opposite to the motion—often referred to as drag force—can be calculated by examining the power exerted by the engine and the constant velocity of the car. Understanding how force interacts with motion allows for the determination of various other physical properties, such as the amount of work done over a distance, the energy consumed or produced, and the overall efficiency of mechanical systems.

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Most popular questions from this chapter

A skydiver is subject to two forces: gravity and air resistance. Falling vertically, she reaches a constant terminal speed at some time after jumping from a plane. Since she is moving at a constant velocity from that time until her chute opens, we conclude from the work-kinetic energy theorem that, over that time interval, a) the work done by gravity is zero. b) the work done by air resistance is zero. c) the work done by gravity equals the negative of the work done by air resistance. d) the work done by gravity equals the work done by air resistance. e) her kinetic energy increases.

You push your couch a distance of \(4.00 \mathrm{~m}\) across the living room floor with a horizontal force of \(200.0 \mathrm{~N}\). The force of friction is \(150.0 \mathrm{~N}\). What is the work done by you, by the friction force, by gravity, and by the net force?

A car of mass \(1214.5 \mathrm{~kg}\) is moving at a speed of \(62.5 \mathrm{mph}\) when it misses a curve in the road and hits a bridge piling. If the car comes to rest in \(0.236 \mathrm{~s}\), how much average power (in watts) is expended in this interval?

A \(95.0-\mathrm{kg}\) refrigerator rests on the floor. How much work is required to move it at constant speed for \(4.00 \mathrm{~m}\) along the floor against a friction force of \(180 .\) N?

Suppose you pull a sled with a rope that makes an angle of \(30.0^{\circ}\) to the horizontal. How much work do you do if you pull with \(25.0 \mathrm{~N}\) of force and the sled moves \(25.0 \mathrm{~m} ?\)

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