Question

Give the numbers of protons, nucleons, neutrons, and electrons in an atom of \({ }_{54}^{134} \mathrm{Xe} .\)

Short answer

Answer: In an atom of \({}_{54}^{134}\mathrm{Xe}\), there are 54 protons, 134 nucleons, 80 neutrons, and 54 electrons.

Step-by-step solution

Determining the Number of Protons

In the given notation, \({}_{54}^{134}\mathrm{Xe}\), the atomic number (Z) is 54. The atomic number represents the number of protons in the nucleus. Therefore, there are 54 protons in this atom.

Determining the Number of Nucleons

In the notation, \({}_{54}^{134}\mathrm{Xe}\), the mass number (A) is 134. The mass number represents the total number of protons and neutrons (nucleons) in the nucleus. Thus, there are 134 nucleons in this atom.

Determining the Number of Neutrons

To find the number of neutrons, we subtract the atomic number (Z) from the mass number (A). In this case, the number of neutrons n is given by: n = A - Z = 134 - 54 = 80 So, there are 80 neutrons in this atom.

Determining the Number of Electrons

Since the atom is neutral, the number of electrons will be equal to the number of protons. Therefore, there are 54 electrons in this atom. To conclude, in an atom of \({}_{54}^{134}\mathrm{Xe}\), there are: - 54 protons - 134 nucleons - 80 neutrons - 54 electrons