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Electrons with the same value of the quantum number \(n\) are said to occupy the same electron shell, \(K, L, M, N,\) or higher. Calculate the maximum allowed number of electrons for the a) \(K\) shell, b) \(L\) shell, and c) \(M\) shell.

Short Answer

Expert verified
Answer: The maximum allowed numbers of electrons for the K, L, and M shells are 2 electrons for the K shell, 8 electrons for the L shell, and 18 electrons for the M shell.

Step by step solution

01

Identify the principal quantum number for each shell

The K, L, and M shell corresponds to the principal quantum number values of n = 1, n = 2, and n = 3, respectively.
02

Apply the formula for maximum number of electrons in a shell

We will use the formula: Maximum number of electrons in a shell = 2n^2 where n is the principal quantum number. a) For the K shell (n = 1): Maximum number of electrons = 2(1)^2 = 2(1) = 2 b) For the L shell (n = 2): Maximum number of electrons = 2(2)^2 = 2(4) = 8 c) For the M shell (n = 3): Maximum number of electrons = 2(3)^2 = 2(9) = 18
03

Present final answers

The maximum allowed number of electrons for each shell are as follows: a) K shell: 2 electrons b) L shell: 8 electrons c) M shell: 18 electrons

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Principal Quantum Number
The principal quantum number, denoted as 'n', is integral to understanding the atomic structure and the arrangement of electrons within an atom. It indicates the relative size and energy of electron shells, as well as their distance from the nucleus. The lowest energy level, closest to the nucleus, is given the principal quantum number 1 (n=1), and the energy levels increase numerically as you move further away.

The principal quantum number also determines the maximum number of electrons that an electron shell can hold. This is calculated using the formula: \(2n^2\), where 'n' is the principal quantum number. For instance, the K shell, which is the innermost shell with n=1, can accommodate up to 2 electrons, as indicated by the formula \(2(1)^2 = 2\).

Understanding this concept is crucial for determining electron configurations and predicting an atom's chemical properties. One way to improve your grasp of this topic is to visualize each electron shell as an 'apartment' where the floor number represents the 'n' value. The higher the floor, the more rooms (places for electrons) are available, following the square of the n value.
Electron Configuration
Electron configuration refers to the distribution of electrons in the atomic orbitals of an element. The configuration is governed by a set of rules, including the Pauli exclusion principle and Hund's rule, and gives insight into an atom’s reactivity, bonding behavior, and magnetic properties. Each element has a unique electron configuration that can be noted using standard notation, which includes the principal quantum number, the type of orbital, and the number of electrons in that orbital.

To achieve a stable state, atoms strive to fill or half-fill their electron shells, following the 'aufbau' principle, which guides the sequence in which orbitals are filled. For example, the configuration for oxygen (with 8 electrons) would be written as 1s² 2s² 2p⁴.

For students, a helpful tip is to utilize the periodic table as a map when writing electron configurations. This map shows how electrons fill up orbitals systematically and why some elements have similar chemical qualities due to their configurations.
Atomic Structure
The atomic structure of an element is a fascinating and complex composition that includes protons, neutrons, and electrons. An atom's nucleus contains protons and neutrons, while electrons orbit the nucleus in various shells and subshells. Each electron shell correlates to a principal quantum number and dictates the atom's electronic architecture.

The understanding of atomic structure is foundational for grasping other chemistry concepts like bonding, periodicity, and molecular geometry. Recognizing how electrons layer in shells and subshells can help map out potential paths for electron transitions, influencing how atoms interact with light and with each other.

For those students finding it difficult to visualize, consider using models or drawings to represent the atomic structure. This can make the concept more tangible, showing the nested layers of electron shells surrounding the nucleus like a set of Russian dolls, each with a maximum capacity determined by the principal quantum number.

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Most popular questions from this chapter

A hydrogen atom is in its fifth excited state, with principal quantum number \(n=6\). The atom emits a photon with a wavelength of \(410 \mathrm{nm}\). Determine the maximum possible orbital angular momentum of the electron after emission.

A muon is a particle very similar to an electron. It has the same charge but its mass is \(1.88 \cdot 10^{-28} \mathrm{~kg}\). a) Calculate the reduced mass for a hydrogen-like muonic atom consisting of a single proton and a muon. b) Calculate the ionization energy for such an atom, assuming that the muon is initially in its ground state.

Section 38.2 established that an electron, if observed in the ground state of hydrogen, is expected to have a speed of \(0.0073 c\). For what nuclear charge \(Z\) would an innermost electron have a speed of approximately \(0.500 c\), when considered classically?

Following the steps used in the text for the hydrogen atom, apply the Bohr model of the atom to derive an expression for a) the radius of the \(n\) th orbit, b) the speed of the electron in the \(n\) th orbit, and c) the energy levels in a hydrogen-like ionized atom with charge number \(Z\) that has lost all of its electrons except for one. Compare the results with the corresponding ones for the hydrogen atom.

An electron in a hydrogen atom is in the \(2 s\) state. Calculate the probability of finding the electron within a Bohr radius \(\left(a_{0}=0.05295 \mathrm{nm}\right)\) of the proton. The \(2 s\) wave function for hydrogen is $$ \psi_{2 s}(r)=\frac{1}{4 \sqrt{2 \pi a_{0}^{3}}}\left(2-\frac{r}{a_{0}}\right) e^{-r / 2 a_{0}} $$ Evaluating the integral is a bit tedious, so you may want to consider using a program such as Mathcad or Mathematica or finding the integral online at http://integrals.wolfram.com/index.jsp.

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