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In a high-speed football game, a running back traveling at \(55.0 \%\) of the speed of light relative to the field throws the ball to a receiver running in the same direction at \(65.0 \%\) of the speed of light relative to the field. The speed of the ball relative to the running back is \(80.0 \%\) of the speed of light. a) How fast does the receiver perceive the speed of the ball to be? b) If the running back shines a flashlight at the receiver, how fast will the photons appear to be traveling to the receiver?

Short Answer

Expert verified
Answer: The receiver perceives the speed of the ball to be 95.39% of the speed of light, and the speed of the photons from the flashlight as perceived by the receiver is 100% of the speed of light (c).

Step by step solution

01

Calculate the velocities in terms of the speed of light

First, convert the given percentages to decimals and multiply by the speed of light (c) to find the velocities of the running back, receiver, and ball relative to each other: Running back: \(0.55c\) Receiver: \(0.65c\) Ball relative to the running back: \(0.80c\)
02

Apply the relativistic velocity addition formula

Use the relativistic velocity addition formula to find the perceived speed of the ball by the receiver: \(v_{BR} = \frac{v_{B} + v_{R}}{1 + \frac{v_{B}v_{R}}{c^2}}\) Here \(v_{BR}\) is the velocity of the ball relative to the receiver, \(v_{B}\) is the velocity of the ball relative to the running back, and \(v_{R}\) is the velocity of the receiver relative to the field.
03

Plug in the values and solve for \(v_{BR}\)

Insert the known velocities into the equation: \(v_{BR} = \frac{0.80c + 0.65c}{1 + \frac{(0.80c)(0.65c)}{c^2}}\) Simplify the equation and solve for \(v_{BR}\): \(v_{BR} = \frac{1.45c}{1 + 0.52}\) \(v_{BR} = \frac{1.45c}{1.52}\) \(v_{BR} = 0.9539c\) So, the receiver perceives the speed of the ball to be \(95.39 \%\) of the speed of light. This solves part (a) of the exercise.
04

Determine the speed of the photons from the flashlight

Since photons travel at the speed of light, they have the maximum possible speed in the universe. No matter the speed of the source or the observer, photons will always appear to travel at the speed of light. Therefore, for part (b), the speed of the photons from the flashlight as perceived by the receiver is \(c\) or \(100 \%\) of the speed of light.

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