Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A gravitational lens should produce a halo effect and not arcs. Given that the light travels not only to the right and left of the intervening massive object but also to the top and bottom, why do we typically see only arcs?

Short Answer

Expert verified
Answer: Gravitational lenses typically produce arc-like images instead of a halo effect due to the elliptical mass distribution of the lensing objects, the geometry of the lensing system, and the rarity of perfect cosmic alignments. These factors contribute to the formation of arcs rather than complete rings in most gravitational lensing situations.

Step by step solution

01

Recall the definition of gravitational lensing

Gravitational lensing is a phenomenon that occurs when light from a distant object, such as a galaxy, is bent around a massive object, such as a galaxy cluster, due to its gravitational field. This bending of light causes the light to take different paths, resulting in distorted and multiple images of the distant object.
02

Understand the arc effect in gravitational lensing

In gravitational lensing, arcs are formed due to the mass distribution of the lensing object. When the mass of the intervening object is not symmetrical or the background object is not perfectly aligned with the lensing object, the light's path becomes distorted, causing the formation of arcs instead of a complete ring.
03

Consider mass distribution and geometry

The intervening massive object, such as a galaxy cluster, generally has an elliptical mass distribution. This uneven distribution of mass results in stronger gravitational lensing effects along the major axis of the elliptical mass profile, causing arc-like images to be more prominent. When a background source is closer to the major axis of the foreground mass distribution, the tangential stretching of its light is more pronounced, forming an elongated, arc-like image.
04

Remember the cosmic alignment

In order for a perfect halo or ring effect to be visible, the alignment of the lensing object, the distant object, and the observer must be nearly perfect. This ideal alignment is quite rare in the universe, making the exact halo effect less common. Instead, what we typically see are arc-like images due to the slightly misaligned positions of objects in cosmic gravitational lensing situations.
05

Conclusion

In conclusion, we typically see arc-like images in gravitational lensing instead of a halo effect due to the elliptical mass distribution of the lensing objects, the geometry of the lensing system, and the rarity of perfect cosmic alignments. The combination of these factors results in the formation of arcs rather than complete rings in most gravitational lensing situations.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In Jules Verne's classic Around the World in Eighty Days, Phileas Fogg travels around the world in, according to his calculation, 81 days. Because he crossed the International Date Line, he actually made it only 80 days. How fast would he have to go in order to have time dilation make 80 days seem like \(81 ?\) (Of course, at this speed, it would take a lot less than 1 day to get around the world.....)

Suppose you are explaining the theory of relativity to a friend, and you tell him that nothing can go faster than \(300,000 \mathrm{~km} / \mathrm{s}\). He says that is obviously false: Suppose a spaceship traveling past you at \(200,000 \mathrm{~km} / \mathrm{s}\), which is perfectly possible according to what you are saying, fires a torpedo straight ahead whose speed is \(200,000 \mathrm{~km} / \mathrm{s}\) relative to the spaceship, which is also perfectly possible; then, he says, the torpedo's speed is \(400,000 \mathrm{~km} / \mathrm{s}\) How would you answer him?

Consider two clocks carried by observers in a reference frame moving at speed \(v\) in the positive \(x\) -direction relative to Earth's rest frame. Assume that the two reference frames have parallel axes and that their origins coincide when clocks at that point in both frames read zero. Suppose the clocks are separated by a distance \(l\) in the \(x^{\prime}\) -direction in their own reference frame; for instance, \(x^{\prime}=0\) for one clock and \(x^{\prime}=I\) for the other, with \(y^{\prime}=z^{\prime}=0\) for both. Determine the readings \(t^{\prime}\) on both clocks as functions of the time coordinate \(t\) in Earth's reference frame.

Consider motion in one spatial dimension. For any velocity \(v_{n}\) define the parameter \(\theta\) via the relation \(v=c \tanh \theta,\) where \(c\) is the speed of light in vacuum. This quantity is called the velocity parameter or the rapidity corresponding to velocity \(v\). a) Prove that for two velocities, which add via a Lorentz transformation, the corresponding velocity parameters simply add algebraically, that is, like Galilean velocities. b) Consider two reference frames in motion at speed \(v\) in the \(x\) -direction relative to one another, with axes parallel and origins coinciding when clocks at the origin in both frames read zero. Write the Lorentz transformation between the two coordinate systems entirely in terms of the velocity parameter corresponding to \(v\) and the coordinates.

In the age of interstellar travel, an expedition is mounted to an interesting star 2000.0 light-years from Earth. To make it possible to get volunteers for the expedition, the planners guarantee that the round-trip to the star will take no more than \(10.000 \%\) of a normal human lifetime. (At the time, the normal human lifetime is 400.00 years.) What is the minimum speed with which the ship carrying the expedition must travel?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free