Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Think of the pupil of your eye as a circular aperture \(5.00 \mathrm{~mm}\) in diameter. Assume you are viewing light of wavelength \(550 . \mathrm{nm},\) to which your eyes are maximally sensitive. a) What is the minimum angular separation at which you can distinguish two stars? b) What is the maximum distance at which you can distinguish the two headlights of a car mounted \(1.50 \mathrm{~m}\) apart?

Short Answer

Expert verified
Answer: The minimum angular separation between two stars that a person can distinguish is approximately 7.68e-3 degrees. The maximum distance at which a person can distinguish the two headlights of a car mounted 1.50 m apart is approximately 11,172.63 meters.

Step by step solution

01

Understand the Rayleigh criterion

According to the Rayleigh criterion, the minimum angular separation (θ) that can be resolved by a circular aperture is given by the formula: θ = 1.22 * (λ / D) where θ - Minimum angular separation in radians λ - Wavelength of the light (in this case, 550 nm) D - Diameter of the aperture (in this case, the pupil diameter: 5.00 mm)
02

Calculate the minimum angular separation between two stars

Using the given values for λ and D, we can calculate the minimum angular separation at which a person can distinguish two stars using the formula mentioned above: Convert wavelength to meters: λ = 550 nm * (1 m / 1e9 nm) = 550e-9 m Convert diameter to meters: D = 5 mm * (1 m / 1000 mm) = 5e-3 m Now, plug these values into the formula: θ = 1.22 * (550e-9 m / 5e-3 m) θ = 1.34e-4 radians. This is the minimum angular separation in radians. To convert to degrees, multiply by (180 / π): θ = 1.34e-4 * (180/π) ≈ 7.68e-3 degrees. Minimum angular separation between two stars is approximately 7.68e-3 degrees.
03

Calculate the maximum distance at which headlights can be distinguished

The angular separation (θ) between the two headlights mounted 1.50 m apart can be related to the distance (d) from an observer by the formula: θ = tan^(-1)(s / d), where s - Separation between the headlights (1.50m) θ - Minimum angular separation (1.34e-4 radians) First, solve for the distance (d) using the minimum angular separation: d = s / tan(θ) d = 1.50 m / tan(1.34e-4) Calculate the distance (d) d ≈ 11,172.63 m The maximum distance at which a person can distinguish the two headlights of a car mounted 1.50 m apart is approximately 11,172.63 meters.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A diffraction grating has \(4.00 \cdot 10^{3}\) slits/cm and has white light \((400 .-700 . \mathrm{nm})\) incident on it. What wavelength(s) will be visible at \(45.0^{\circ} ?\)

X-rays with a wavelength of \(1.00 \mathrm{nm}\) are scattered off two small tumors in a human body. If the two tumors are a distance of \(10.0 \mathrm{~cm}\) away from the X-ray detector, which has an entrance aperture of diameter \(1.00 \mathrm{~mm}\), what is the minimum separation between the two tumors that will allow the X-ray detector to determine that there are two tumors instead of one?

A pair of thin slits is separated by a distance \(d=1.40 \mathrm{~mm}\) and is illuminated with light of wavelength \(460.0 \mathrm{nm} .\) What is the separation between adjacent interference maxima on a screen a distance \(L=2.90 \mathrm{~m}\) away? a) \(0.00332 \mathrm{~mm}\) b) \(0.556 \mathrm{~mm}\) c) \(0.953 \mathrm{~mm}\) d) \(1.45 \mathrm{~mm}\) e) \(3.23 \mathrm{~mm}\)

Which type of the light incident on a grating with 1000 rulings with a spacing of \(2.00 \mu \mathrm{m}\) would produce the largest number of maxima on a screen \(5.00 \mathrm{~m}\) away? \(?\) a) blue light of wavelength \(450 \mathrm{nm}\) b) green light of wavelength \(550 \mathrm{nm}\) c) yellow light of wavelength \(575 \mathrm{nm}\) d) red light of wavelength \(625 \mathrm{nm}\) e) need more information

What is the wavelength of the X-rays if first-order Bragg diffraction is observed at \(23.0^{\circ}\) relative to the crystal surface, with an interatomic distance of \(0.256 \mathrm{nm} ?\)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free