Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A common interference setup for seeing Newton's rings consists of a plano- convex lens placed on a plane mirror and illuminated from above at normal incidence with monochromatic light. In an experiment using a plano-convex lens with focal length \(f=80.00 \mathrm{~cm}\) and index of refraction \(n_{1}=1.500\), the radius of the third bright circle is found to be \(0.8487 \mathrm{~mm} .\) Determine the wavelength of the monochromatic light

Short Answer

Expert verified
Answer: Approximately 590 nm.

Step by step solution

01

Calculate the radius of curvature of the lens surface

In this step, we will use the lens-maker's formula to determine the radius of curvature of the lens surface: \( \frac{1}{f} = (n_1 - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right) \) Since the lens is plano-convex, the radius of curvature of the plane side is infinite (\( R_2 \rightarrow \infty\)), which simplifies the lens-maker's formula to: \( \frac{1}{f} = (n_1 - 1) \left( \frac{1}{R_1}\right) \) We can now solve for \(R_1\): \( R_1 = \frac{1}{(n_1 - 1)\frac{1}{f}} \) Plug in the given values: \( R_1 = \frac{1}{(1.5 - 1)\frac{1}{80}} = 160 \,\text{cm} \)
02

Determine the order and radius of the bright circle

In this step, we need to identify the order (m) of the bright circle. For the third bright circle, the order is m = 3. We are also given the radius of the third bright circle, which is r = 0.8487 mm.
03

Calculate the wavelength

Using the radius of the bright circle, we can now use the radius formula for bright circles in Newton's rings: \( r^2 = m\lambda R_1 - \frac{m^2}{4}\lambda^2 \) Since we have all the values except for the wavelength \(\lambda\), we can solve for it: \( \lambda = \frac{4r^2}{4mR_1 - m^2} = \frac{4(0.8487 \times 10^{-3})^2}{4(3)(0.16) - 3^2} \,\text{m} \) Finally, calculate the wavelength: \( \lambda = \frac{4(0.8487 \times 10^{-3})^2}{4(0.48) - 9} \times 10^9 \,\text{nm} \approx 590 \,\text{nm} \) So, the wavelength of the monochromatic light is approximately 590 nm.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Interference in Physics
Interference refers to the phenomenon where two or more waves superimpose to form a resultant wave of greater, lower, or the same amplitude. In the context of optics, this principle is observed when light waves coincide, producing patterns of light and darkness. A classic example is the creation of Newton's rings, an interference pattern, typically observed when a plano-convex lens is placed on a flat glass surface, and monochromatic light is shone upon it.

These patterns are composed of a series of concentric rings. They arise due to the interference of light that reflects off the top surface of the lens and the light reflecting from the bottom surface, where it contacts the glass. When the path difference between these two sets of reflected waves corresponds to a whole number of wavelengths, constructive interference occurs, creating bright rings. Conversely, destructive interference generates dark rings. This setup is not only fascinating but a practical application of interference, as it can be employed to measure the wavelength of light or the small thickness differences between surfaces.
Lens-Maker's Formula
The lens-maker's formula is a fundamental equation in optics that relates the focal length of a lens to its refractive index and the radii of curvature of its two surfaces. Expressed as \[\begin{equation} \frac{1}{f} = (n - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right), \end{equation}\]where f is the focal length, n is the refractive index of the lens material, and R1 and R2 are the radii of curvature of the lens's first and second surfaces, respectively. In the case of a plano-convex lens, like in our exercise, one radius (R2) is infinite because it's a flat surface, simplifying the calculation.

Understanding this formula is crucial for lens design and implementation in all sorts of optical devices from eyeglasses to cameras. By manipulating the shape of the lens and knowing the properties of the material, engineers can determine the focal length required for a particular application, making this formula a cornerstone of optical science and engineering.
Monochromatic Light Wavelength
The term 'monochromatic' originates from the Greek words 'mono,' meaning 'single' and 'chroma,' meaning 'color'. In physics, monochromatic light refers to light of a single wavelength, thus a single color, which is essential for creating clear and distinct interference patterns. Since different wavelengths of light correspond to different colors in the visible spectrum, the wavelength of monochromatic light used in experiments like the Newton's rings can reveal information about the color observed.

In practice, this concept is significant when measuring the wavelength of light using interference patterns. By analyzing the geometry of these patterns, as done in the context of Newton's rings, scientists can determine the precise wavelength of the source light. The problem we're addressing uses this principle to calculate the wavelength of the light involved by understanding the interference pattern created when monochromatic light shines upon a plano-convex lens laying on a reflective surface. This precise calculation is central to various applications, ranging from spectroscopy to the calibration of optical instruments.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In Young's double-slit experiment, both slits were illuminated by a laser beam and the interference pattern was observed on a screen. If the viewing screen is moved farther from the slits, what happens to the interference pattern? a) The pattern gets brighter. b) The pattern gets brighter, and the maxima are closer together. c) The pattern gets less bright, and the maxima are farther apart. d) There is no change in the pattern. e) The pattern becomes unfocused. f) The pattern disappears.

The single-slit diffraction pattern shown in the figure was produced with light of wavelength \(495 \mathrm{nm}\). The screen on which the pattern was projected is located a distance of \(2.77 \mathrm{~m}\) from the slit. The slit has a width of \(2.73 \mathrm{~mm}\). What is the width \(w\) of the central maximum?

An airplane is made invisible to radar by coating it with a 5.00 -mm-thick layer of an antireflective polymer with index of refraction \(n=1.50 .\) What is the wavelength of the radar waves for which the plane is made invisible?

Suppose the thickness of a thin soap film \((n=1.32)\) surrounded by air is nonuniform and gradually tapers. Monochromatic light of wavelength \(550 \mathrm{nm}\) illuminates the film. At the thinnest end, a dark fringe is observed. How thick is the film at the two dark fringes closest to that fringe?

The single-slit diffraction pattern shown in the figure was produced with light from a laser. The screen on which the pattern was projected is located a distance of \(3.17 \mathrm{~m}\) from the slit. The slit has a width of \(0.555 \mathrm{~mm}\). The width of the central maximum is \(w=5.81 \mathrm{~mm}\). What is the wavelength of the laser light?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free