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What is the electric field amplitude of an electromagnetic wave whose magnetic field amplitude is \(5.00 \cdot 10^{-3} \mathrm{~T} ?\)

Short Answer

Expert verified
Answer: The electric field amplitude of the electromagnetic wave is \(1.50 \cdot 10^6 \mathrm{~V/m}\).

Step by step solution

01

Identify the relationship between electric and magnetic field amplitudes

In electromagnetic waves, the electric field amplitude (E) and the magnetic field amplitude (B) are related by the equation: E = c * B Where E is the electric field amplitude, B is the magnetic field amplitude, and c is the speed of light in a vacuum (\(3.00 \cdot 10^8 \mathrm{~m/s}\)). This relationship is derived from Maxwell's equations for electromagnetic waves.
02

Substitute given values into the equation

We are given the magnetic field amplitude as \(B = 5.00 \cdot 10^{-3} \mathrm{~T}\). We can substitute this value into the E = c * B equation: E = \((3.00 \cdot 10^8 \mathrm{~m/s})\) * \((5.00 \cdot 10^{-3} \mathrm{~T})\)
03

Perform the multiplication

Now, multiply the speed of light with the given magnetic field amplitude: E = \(1.50 \cdot 10^6 \mathrm{~V/m}\)
04

Write the final answer

The electric field amplitude of the electromagnetic wave is \(1.50 \cdot 10^6 \mathrm{~V/m}\).

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