Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

If you use a parallel plate capacitor with air in the gap between the plates as part of a series RLC circuit in a generator, you can measure current flowing through the generator. Why is it that the air gap in the capacitor does not act like an open switch, blocking all current flow in the circuit?

Short Answer

Expert verified
Answer: The air gap in a parallel plate capacitor in a series RLC circuit does not act like an open switch because the capacitor stores and releases energy as an electric field, which allows an alternating current (AC) to flow through the circuit. As the frequency of the applied signal increases, the capacitive reactance decreases, allowing more current to flow through the capacitor.

Step by step solution

01

Capacitor functionality

A capacitor is an electronic component that can store and release electrical energy. In a parallel plate capacitor, two conductive plates separated by a dielectric (air, in this case) are used. When a voltage is applied across the capacitor, an electric field is established, and as a result, positive and negative charges accumulate on the plates. The energy is stored in this electric field until the voltage is removed or changed.
02

Series RLC circuit

A series RLC circuit is a combination of a resistor (R), an inductor (L), and a capacitor (C) connected in series. In this circuit, the voltage across all the components (V_R, V_L, and V_C) is equal to the total voltage of the circuit (V_T). The current (I) passing through each component is the same due to the series connection, while the voltages of each component differ. The voltage across the resistor is in phase with the current, while for the inductor and capacitor, there's a 90-degree phase difference.
03

Role of air gap

In a capacitor with an air gap, the air acts as a dielectric material between the two plates. This dielectric prevents the flow of charge directly between the plates. Nevertheless, a current does flow into and out of the plates as energy is stored and released by the capacitor.
04

Alternate current (AC) and capacitive reactance

In an AC circuit, the current alternates directions, and the voltage across the capacitor's plates also changes periodically. As the stored energy depends on the voltage applied, this energy storage and release process happens cyclically resulting in AC current flowing through the circuit. The effective opposition to the flow of AC current in a capacitor is known as capacitive reactance (X_C), which is calculated as X_C = 1/(2Ï€fC), where f is the frequency of the AC signal and C is the capacitance. It shows that the current flowing through the air gap capacitor is inversely proportional to its reactance, meaning that as the frequency of the AC signal increases, the reactance decreases, and more current flows through the capacitor.
05

Conclusion

The air gap in a parallel plate capacitor in a series RLC circuit does not act like an open switch because the capacitor stores and releases energy as an electric field, which allows an alternating current (AC) to flow through the circuit. As the frequency of the applied signal increases, the capacitive reactance decreases, allowing more current to flow through the capacitor.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A 75,000 -W light bulb (yes, there are such things!) operates at \(I_{\mathrm{rms}}=200 . \mathrm{A}\) and \(V_{\mathrm{rms}}=440 . \mathrm{V}\) in a \(60.0-\mathrm{Hz} \mathrm{AC}\) circuit. Find the resistance, \(R,\) and self- inductance, \(L,\) of this bulb. Its capacitive reactance is negligible.

An electromagnet consists of 200 loops and has a length of \(10.0 \mathrm{~cm}\) and a cross-sectional area of \(5.00 \mathrm{~cm}^{2} .\) Find the resonant frequency of this electromagnet when it is attached to the Earth (treat the Earth as a spherical capacitor).

A transformer with \(400 .\) turns in its primary coil and \(20 .\) turns in its secondary coil is designed to deliver an average power of \(1200 .\) W with a maximum voltage of \(60.0 \mathrm{~V}\). What is the maximum current in the primary coil?

The discussion of \(\mathrm{RL}, \mathrm{RC},\) and \(\mathrm{RLC}\) circuits in this chapter has assumed a purely resistive resistor, one whose inductance and capacitance are exactly zero. While the capacitance of a resistor can generally be neglected, inductance is an intrinsic part of the resistor. Indeed, one of the most widely used resistors, the wire-wound resistor, is nothing but a solenoid made of highly resistive wire. Suppose a wire-wound resistor of unknown resistance is connected to a DC power supply. At a voltage of \(V=10.0 \mathrm{~V}\) across the resistor, the current through the resistor is \(1.00 \mathrm{~A}\) Next, the same resistor is connected to an AC power source providing \(V_{\mathrm{rms}}=10.0 \mathrm{~V}\) at a variable frequency. When the frequency is \(20.0 \mathrm{kHz}, \mathrm{a}\) current, \(I_{\mathrm{rms}}=0.800 \mathrm{~A},\) is measured through the resistor. a) Calculate the resistance of the resistor. b) Calculate the inductive reactance of the resistor. c) Calculate the inductance of the resistor. d) Calculate the frequency of the AC power source at which the inductive reactance of the resistor exceeds its resistance.

Why can't a transformer be used to step up or step down the voltage in a DC circuit?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free