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In ideal projectile motion, the velocity and acceleration of the projectile at its maximum height are, respectively, a) horizontal, vertical downward. b) horizontal, zero. c) zero, zero. d) zero, vertical downward. e) zero, horizontal.

Short Answer

Expert verified
Answer: a) horizontal, vertical downward

Step by step solution

01

Understanding Ideal Projectile Motion

Ideal projectile motion is a two-dimensional motion under the influence of gravity. It is called "ideal" because it assumes no air resistance or other external forces except gravity. In this motion, an object is launched at an angle to the horizontal, and its path traces a parabolic trajectory.
02

Finding Velocity at Maximum Height

At the maximum height, the vertical component of the projectile's velocity becomes zero because the object has reached its highest point and is not moving upward or downward momentarily. However, the horizontal component of the velocity remains constant throughout the motion, as there are no external forces acting on it in the horizontal direction. Hence, at the maximum height, the velocity of the projectile is horizontal.
03

Finding Acceleration at Maximum Height

Acceleration in ideal projectile motion is constant and is always directed downward, due to gravity. This acceleration is known as the gravitational acceleration (g) and is usually approximated to 9.81 m/s². It is essential to note that acceleration due to gravity always acts on the projectile, even at its maximum height. Thus, the acceleration of the projectile at its maximum height is vertical downward. Using the information provided in steps 2 and 3, we can now answer the exercise question. The velocity of the projectile at its maximum height is horizontal, and its acceleration is vertical downward. Therefore, the correct answer is: a) horizontal, vertical downward.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Velocity at Maximum Height
When discussing ideal projectile motion, a crucial point to understand is the projectile's velocity at its maximum height. Imagine throwing a ball at an upward angle; as it rises, it slows down due to gravity. At the peak of its ascent, known as the maximum height, the vertical component of its velocity is momentarily nil. It's at this point that the ball is neither climbing nor falling; it's paused in the vertical sense.
However, the horizontal component of its velocity doesn't cease. It persists unchanged because, in an ideal scenario, we disregard air resistance and other horizontal forces. Thus, at the zenith of its trajectory, the projectile sails onward solely with a horizontal velocity. This simplistic view of motion helps break down the complex journey of a projectile into manageable concepts, aiding students in their understanding of an object in flight.
Acceleration Due to Gravity
The acceleration due to gravity is an ever-present influence in projectile motion. Regardless of the projectile's position—whether ascending, descending, or at its apex—gravity exerts a consistent pull downward. This force is reflected as an acceleration, directly toward the Earth's center, and is symbolized as 'g', averaging approximately 9.81 m/s².
Students might wonder, 'Does gravity cease at the top?' The answer is a definitive 'no'. Even when the projectile reaches its maximum height and the upward movement halts, gravity is still at work, ensuring that the projectile will resume its descent. Hence, throughout the entire trajectory, the projectile retains this unwavering downward acceleration, underlining gravity's relentless influence on terrestrial objects.
Parabolic Trajectory
The term parabolic trajectory is often associated with ideal projectile motion, illustrating the graceful arc a projectile describes when launched at an angle into a gravity field with no air resistance. Why is it parabolic? It's derived from the fact that the motion of the projectile, influenced by a consistent gravitational pull, forms a shape that is symmetrically curved—a shape known as a parabola.
Visualize a basketball player making a jump shot; the ball arcs through the air, climbing, peaking, then descending into the hoop, assuming a parabolic path. This is not just an aesthetic marvel; it’s a fundamental concept demonstrating kinetic energy conversion into potential energy and back, all under the influence of gravity. Understanding the parabolic trajectory enhances a student's grasp of the forces at play and how energy is conserved and transformed in an isolated system like ideal projectile motion.

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Most popular questions from this chapter

During one of the games, you were asked to punt for your football team. You kicked the ball at an angle of \(35.0^{\circ}\) with a velocity of \(25.0 \mathrm{~m} / \mathrm{s}\). If your punt goes straight down the field, determine the average speed at which the running back of the opposing team standing at \(70.0 \mathrm{~m}\) from you must run to catch the ball at the same height as you released it. Assume that the running back starts running as the ball leaves your foot and that the air resistance is negligible.

Two cannonballs are shot in sequence from a cannon, into the air, with the same muzzle velocity, at the same launch angle. Based on their trajectory and range, how can you tell which one is made of lead and which one is made of wood. If the same cannonballs were launched in vacuum, what would your answer be?

A blimp is ascending at the rate of \(7.50 \mathrm{~m} / \mathrm{s}\) at a height of \(80.0 \mathrm{~m}\) above the ground when a package is thrown from its cockpit horizontally with a speed of \(4.70 \mathrm{~m} / \mathrm{s}\). a) How long does it take for the package to reach the ground? b) With what velocity (magnitude and direction) does it hit the ground?

During the 2004 Olympic Games, a shot putter threw a shot put with a speed of \(13.0 \mathrm{~m} / \mathrm{s}\) at an angle of \(43.0^{\circ}\) above the horizontal. She released the shot put from a height of \(2.00 \mathrm{~m}\) above the ground. a) How far did the shot put travel in the horizontal direction? b) How long was it until the shot put hit the ground?

A projectile is launched twice from a height \(y_{0}=0\) at a given launch speed, \(v_{0} .\) The first launch angle is \(30.0^{\circ} ;\) the second angle is \(60.0^{\circ} .\) What can you say about the range \(R\) of the projectile in these two cases? a) \(R\) is the same for both cases. b) \(R\) is larger for a launch angle of \(30.0^{\circ}\). c) \(R\) is larger for a launch angle of \(60.0^{\circ}\). d) None of the preceding statements is true.

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