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Suppose the resistance of the resistor in Solved Problem 29.1 is increased by a factor of \(2 .\) By what factor does the power dissipated in the resistor change? a) \(\frac{1}{2}\) b) 2 c) 4 d) 8 e) 16

Short Answer

Expert verified
Answer: (a) 1/2

Step by step solution

01

Understand the given information

We are given that the resistance of the resistor is increased by a factor of 2. Let the initial resistance be R, and the new resistance be R'. So, R' = 2R. We need to find the factor by which the power dissipated in the resistor changes.
02

Recall the formula for power dissipation

The formula for power dissipation in a resistor is P = V^2/R, where P is the power dissipated, V is the voltage across the resistor, and R is the resistance of the resistor.
03

Calculate the initial power dissipation

Let's denote the initial power dissipation as P1. Using the formula P = V^2/R, we can calculate P1 as follows: P1 = V^2/R
04

Calculate the new power dissipation

Now, let's denote the new power dissipation as P2. Since the resistance is increased by a factor of 2, we have R' = 2R. Using the formula P = V^2/R, we can calculate P2 as follows: P2 = V^2/R' Since R' = 2R, we can substitute this into the equation: P2 = V^2/(2R)
05

Find the ratio of the new power to the initial power

To find the factor by which the power dissipated in the resistor changes, we need to find the ratio of the new power to the initial power: Factor = P2/P1 Substitute the expressions for P2 and P1: Factor = (V^2/(2R))/(V^2/R)
06

Simplify the expression

To simplify the expression, we can cancel out V^2 and then solve for the Factor: Factor = (1/(2R))/(1/R) Factor = (R/2R) = 1/2 The factor by which the power dissipated in the resistor changes is 1/2, which corresponds to answer (a).

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