Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A toroidal magnet has an inner radius of \(1.351 \mathrm{~m}\) and an outer radius of \(1.541 \mathrm{~m}\). The wire carries a 49.13 -A current, and there are 24,945 turns in the toroid. What is the magnetic field at a distance of \(1.446 \mathrm{~m}\) from the center of the toroid?

Short Answer

Expert verified
Answer: The magnetic field at a distance of 1.446 m from the center of the toroidal magnet is approximately 0.0263 T.

Step by step solution

01

Understand the given information and find the relevant formula

We are given the inner radius (\(R_1 = 1.351\mathrm{~m}\)), the outer radius (\(R_2 = 1.541\mathrm{~m}\)), the current in the wire (\(I = 49.13\mathrm{~A}\)), and the number of turns in the magnet (\(N = 24,945\)). We need to find the magnetic field (\(B\)) at a distance \(r = 1.446\mathrm{~m}\) from the center of the toroid. Using Ampere's law, the formula for the magnetic field at any point inside the toroidal magnet is: \(B = \frac{\mu_0 \cdot N \cdot I}{2 \pi r}\), where \(\mu_0\) is the permeability of free space, which is approximately \(4 \pi \times 10^{-7} \mathrm{T \cdot m/A}\).
02

Check if the distance is within the magnet boundary

Since we need to calculate the magnetic field at a distance \(r = 1.446\mathrm{~m}\) from the center, we must first check if this distance lies within the boundary of the toroidal magnet. As it falls between the inner radius (\(1.351\mathrm{~m}\)) and the outer radius (\(1.541\mathrm{~m}\)), the magnetic field can be found using the above formula.
03

Calculate the magnetic field

Now, we can calculate the magnetic field using the given data and the formula from Step 1. \(B = \frac{\mu_0 \cdot N \cdot I}{2 \pi r} = \frac{(4 \pi \times 10^{-7} \mathrm{T \cdot m/A}) \cdot 24,945 \cdot 49.13\mathrm{~A}}{2 \pi \cdot 1.446\mathrm{~m}}\) Solving this equation, we get, \(B \approx 0.0263\mathrm{~T}\) So, the magnetic field at a distance of \(1.446\mathrm{~m}\) from the center of the toroid is approximately \(0.0263\mathrm{~T}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ampere's Law
Ampere's Law is a fundamental rule in electromagnetism that relates the magnetic field around a closed loop to the electric current passing through it. The beauty of Ampere's Law is in its simplicity; it states that the line integral of the magnetic field along a closed path is directly proportional to the net electric current enclosed by the path. This can be mathematically expressed as:
Toroidal Magnet
A toroidal magnet, often simply termed a 'toroid,' is a donut-shaped magnet characterized by its continuous, ring-like form, which creates a closed magnetic circuit. The toroid's shape is essential because it confines most of the magnetic field within the doughnut, with very little magnetic field escaping outside it. As a result, toroidal magnets are prevalent in scientific and medical equipment, where magnetic fields need to be precise and concentrated.
Permeability of Free Space
The permeability of free space, denoted as \( \mu_0 \), is a fundamental physical constant which represents the capability of the vacuum to permit the passage of magnetic field lines. It is a crucial parameter in Ampere's Law and is given the value of approximately \( 4 \pi \times 10^{-7} \) Tesla meter per ampere (T·m/A). When determining the strength of the magnetic field in a vacuum, or in our example, inside a toroid with air as the medium, it is this permeability that we consider.
Magnetic Field Calculation
The calculation of the magnetic field within a toroidal magnet demands attention to the symmetry of the toroid and the uniformity of the current distribution. Using Ampere's Law, the calculation is straightforward for points inside the toroid. Matters become more complex at points at the edge or outside the toroidal structure, as these locations involve different field considerations. In the given exercise, the expressions shine due to the idealistic scenario of a well-defined, symmetrical toroid.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Parallel wires, a distance \(D\) apart, carry a current, \(i\), in opposite directions as shown in the figure. A circular loop, of radius \(R=D / 2,\) has the same current flowing in a counterclockwise direction. Determine the magnitude and the direction of the magnetic field from the loop and the parallel wires at the center of the loop, as a function of \(i\) and \(R\).

A square box with sides of length \(1.00 \mathrm{~m}\) has one corner at the origin of a coordinate system, as shown in the figure. Two coils are attached to the outside of the box. One coil is on the box face that is in the \(x z\) -plane at \(y=0\), and the second is on the box face in the \(y z\) -plane at \(x=1.00 \mathrm{~m} .\) Each of the coils has a diameter of \(1.00 \mathrm{~m}\) and contains 30.0 turns of wire carrying a current of \(5.00 \mathrm{~A}\) in each turn. The current in each coil is clockwise when the coil is viewed from outside the box. What are the magnitude and the direction of the magnetic field at the center of the box?

The magnetic dipole moment of the Earth is approximately \(8.0 \cdot 10^{22} \mathrm{~A} \mathrm{~m}^{2}\). The source of the Earth's magnetic field is not known; one possibility might be the circulation of ions in the Earth's molten outer core. Assume that the circulating ions move a circular loop of radius \(2500 \mathrm{~km} .\) What "current" must they produce to yield the observed field?

Two identical coaxial coils of wire of radius \(20.0 \mathrm{~cm}\) are directly on top of each other, separated by a 2.00 -mm gap. The lower coil is on a flat table and has a current \(i\) in the clockwise direction; the upper coil carries an identical current and has a mass of \(0.0500 \mathrm{~kg} .\) Determine the magnitude and the direction that the current in the upper coil has to have to keep it levitated at the distance \(2.00 \mathrm{~mm}\) above the lower coil.

Consider an electron to be a uniformly dense sphere of charge, with a total charge of \(-e=-1.602 \cdot 10^{-19} \mathrm{C}\), spinning at an angular frequency, \(\omega\). a) Write an expression for its classical angular momentum of rotation, \(L\) b) Write an expression for its magnetic dipole moment, \(\mu\). c) Find the ratio, \(\gamma_{e}=\mu / L,\) known as the gyromagnetic ratio.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free