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Suppose that the magnetic field of the Earth were due to a single current moving in a circle of radius \(2.00 \cdot 10^{3} \mathrm{~km}\) through the Earth's molten core. The strength of the Earth's magnetic field on the surface near a magnetic pole is about \(6.00 \cdot 10^{-5} \mathrm{~T}\). About how large a current would be required to produce such a field?

Short Answer

Expert verified
Answer: The current required is approximately 1.91 × 10^7 A.

Step by step solution

01

Recall the formula for the magnetic field strength of a circular loop

The magnetic field strength (B) at the center of a circular current loop of radius (R) is given by the formula: B = \cfrac{\mu_0 I}{2R} Where I is the current in the loop, and \mu_0 is the permeability of free space, approximately 4π × 10^{-7} T m/A.
02

Rearrange the formula to solve for the current I

We can rearrange the formula for the magnetic field strength to solve for the current (I) as follows: I = \cfrac{2RB}{\mu_0}
03

Substitute the known values into the formula and calculate the current

We are given the radius (R) as 2.00 × 10^3 km = 2.00 × 10^6 m, and the magnetic field strength (B) as 6.00 × 10^{-5} T. We can substitute these values, along with the permeability of free space, into the formula and calculate the current (I): I = \cfrac{2(2.00\times10^{6}\mathrm{m})(6.00\times10^{-5}\mathrm{T})}{4\pi\times10^{-7}\mathrm{Tm/A}}
04

Perform the numerical calculation

Multiplying the values and simplifying the units, we can find the required current: I = \cfrac{2.4\times10^{1}\mathrm{TA}}{4\pi\times10^{-7}\mathrm{Tm/A}} = 2.4\times10^{1}\mathrm{TA} \times \cfrac{1}{4\pi\times10^{-7}\mathrm{Tm/A}} = 1.91 \times 10^{7} A
05

Write down the result

The current required to produce the given magnetic field strength near a magnetic pole is approximately 1.91 × 10^7 A.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Field Strength
Understanding magnetic field strength is crucial when delving into electromagnetism. It's a measure of the magnetic force concentration at a given point in space, typically measured in Teslas (T) in the International System of Units (SI). Imagine the magnetic field as lines moving from the north pole to the south pole of a magnet; where the lines are closer together, the field strength is greater.

When considering Earth's magnetic field, the strength varies depending on the geographic location. Near the magnetic poles, it is stronger and can be approximated to be around 6.00 x 10^-5 T. This information is vital when assessing the required current to generate a similar field using electric currents, as done in the example problem. Just like a bar magnet with its field lines, the Earth generates its magnetic field, which is crucial for navigation, protecting us from solar wind, and a host of other ecological and technological processes.
Permeability of Free Space
The permeability of free space, denoted by the symbol \( \mu_0 \), is a fundamental physical constant. It describes how easily a magnetic field can permeate through the vacuum of space. Essentially, it is the degree of magnetization that a material obtains in response to an applied magnetic field.

In our calculations, \( \mu_0 \) plays a pivotal role as it links the electric current flowing through a wire (or loop) to the resulting magnetic field. Its value is approximately 4\pi x 10^-7 Tm/A. With this constant, we can calculate the magnetic effects of electric currents on a theoretical level and apply these calculations to real-world problems like determining the hypothetical electric current that could generate Earth's magnetic field.
Magnetic Field of Current Loop
A current loop generates a magnetic field with a pattern similar to that of a simple bar magnet and is described by its own set of rules. The strength of the magnetic field at the center of a circular current loop is a function of the current flowing through the loop, the radius of the loop, and the permeability of the free space.

The formula for this is \( B = \cfrac{\mu_0 I}{2R} \), where \(B\) is the magnetic field strength, \(I\) is the current, and \(R\) is the radius. In the context of the Earth-like magnetic field problem, we imagine the Earth's core as such a loop with current flowing through it, and we use this formula to back-calculate the necessary current. The simplicity of the formula belies the complex interaction of electric current and magnetic fields in space, reflecting one of the many elegant symmetries in physics.
Magnetic Field Calculation
Calculating the magnetic field involves using the aforementioned principles together with mathematical formulas specific to the scenario. For instance, with a simple cylindrical current loop, the Biot-Savart Law could be used. However, the provided exercise simplifies the process considerably, giving us a direct proportionality that delineates magnetic field strength in terms of the current and loop radius.

By rearranging the formula to solve for the current when the magnetic field strength and loop radius are known, you can evaluate the necessary realities to recreate certain field conditions. This process demonstrates the practical side of theoretical physics, allowing us to retrofit our formulas to imagine how nature works, or even to assess what's required to mimic natural phenomena, such as the Earth's magnetic field, with human-engineered solutions.

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Most popular questions from this chapter

In a magneto-optic experiment, a liquid sample in a \(10-\mathrm{mL}\) spherical vial is placed in a highly uniform magnetic field, and a laser beam is directed through the sample. Which of the following should be used to create the uniform magnetic field required by the experiment? a) a \(5-\mathrm{cm}\) -diameter flat coil consisting of one turn of 4 -gauge wire b) a \(10-\mathrm{cm}\) -diameter, 20 -turn, single-layer, tightly wound coil made of 18-gauge wire c) a 2 -cm-diameter, \(10-\mathrm{cm}\) -long, tightly wound solenoid made of 18 -gauge wire d) a set of two coaxial \(10-\mathrm{cm}\) -diameter coils at a distance of \(5 \mathrm{~cm}\) apart, each consisting of one turn of 4 -gauge wire

A circular wire loop has a radius \(R=0.12 \mathrm{~m}\) and carries a current \(i=0.10 \mathrm{~A} .\) The loop is placed in the \(x y\) -plane in a uniform magnetic field given by \(\vec{B}=-1.5 \hat{z} \mathrm{~T},\) as shown in the figure. Determine the direction and the magnitude of the loop's magnetic moment and calculate the potential energy of the loop in the position shown. If the wire loop can move freely, how will it orient itself to minimize its potential energy, and what is the value of the lowest potential energy?

An electron moves in a straight line at a speed of \(5.00 \cdot 10^{6} \mathrm{~m} / \mathrm{s}\). What are the magnitude and the direction of the magnetic field created by the moving electron at a distance \(d=5.00 \mathrm{~m}\) ahead of it on its line of motion? How does the answer change if the moving particle is a proton?

Two long, straight wires are parallel to each other. The wires carry currents of different magnitudes. If the amount of current flowing in each wire is doubled, the magnitude of the force between the wires will be a) twice the magnitude of the original force. b) four times the magnitude of the original force. c) the same as the magnitude of the original force. d) half of the magnitude of the original force.

The wire in the figure carries a current \(i\) and contains a circular arc of radius \(R\) and angle \(\pi / 2\) and two straight sections that are mutually perpendicular and, if extended, would intersect the center, \(C,\) of the arc. What is the magnetic field at point \(C\) due to the wire? a) \(B=\frac{\mu_{0} i}{2 R}\) b) \(B=\frac{\mu_{0} i}{4 R}\) c) \(B=\frac{\mu_{0} i}{6 R}\) d) \(B=\frac{\mu_{0} i}{8 R}\) e) \(B=\frac{\mu_{0} i}{12 R}\)

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