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A semicircular loop of wire of radius \(R\) is in the \(x y\) -plane, centered about the origin. The wire carries a current, \(i\), counterclockwise around the semicircle, from \(x=-R\) to \(x=+R\) on the \(x\) -axis. A magnetic field, \(\vec{B},\) is pointing out of the plane, in the positive \(z\) -direction. Calculate the net force on the semicircular loop.

Short Answer

Expert verified
Answer: The net force on the semicircular loop is 0 (zero).

Step by step solution

01

Set up the integral for the net force

To find the net force on the semicircle, we first need to set up an integral for the force experienced by an infinitesimal length of wire, \(\vec{dF} = i\vec{dl} \times \vec{B}\). The semicircle can be parameterized using polar coordinates as \(\vec{r}(\theta) = R \hat{r}(\theta)\), where the angle \(\theta\) varies from \(-\pi\) to \(\pi\). This parameterization allows us to determine the infinitesimal length vector in polar coordinates, which is given by \(\vec{dl}(\theta) = Rd\theta \hat{\theta}\).
02

Calculate the cross product

Now we need to calculate the cross product of \(\vec{dl}\) and \(\vec{B}\). Since \(\vec{B}\) points in the positive \(z\)-direction, the cross product simplifies to: \begin{align*} \vec{dF} = i\vec{dl} \times \vec{B} = i(Rd\theta \hat{\theta}) \times (B \hat{z}) = iR B d\theta (\hat{\theta} \times \hat{z})\text{.} \end{align*} To express this cross product in polar coordinates, we recall that \(\hat{\theta} \times \hat{z} = -\hat{r}\); hence, the force experienced by an infinitesimal length of wire is \(\vec{dF} = -iRB d\theta \hat{r}\).
03

Integrate over the semicircle

Now we integrate the force \(\vec{dF}\) over the entire semicircle: \begin{align*} \vec{F} = \int_{-\pi}^{\pi} \vec{dF} = -i R B\int_{-\pi}^{\pi} d\theta \hat{r}(\theta)\text{.} \end{align*} Since \(\hat{r}(\theta)\) has equal and opposite contributions from each half of the semicircle, the net force on the loop is zero: \begin{align*} \vec{F} = -i R B\int_{-\pi}^{\pi} d\theta \hat{r}(\theta) = \vec{0}\text{.} \end{align*} The net force on the semicircular loop is \(\vec{F}=\vec{0}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Field
Imagine a magnetic field as a region where magnetic forces can act. This invisible field can be visualized through its effects, such as the alignment of iron filings or the motion of a compass needle.

A simple yet powerful way to represent magnetic fields is through arrows, with each arrow depicting the field's direction and strength at a given point. In our problem, the magnetic field vector, denoted as \(\vec{B}\), points out of the page, following the right-hand rule. The direction is critical, as it influences the outcome when we apply the concept of the cross product to determine the force exerted on a current-carrying wire.
Cross Product in Physics
In physics, the cross product is a binary operation on two vectors in three-dimensional space. It provides a vector perpendicular to both original vectors, with a magnitude equal to the area of the parallelogram that the vectors span.

In the context of our exercise, we use the cross product to calculate the magnetic force on a segment of current-carrying wire. Following the formula \(\vec{F} = i\vec{dl} \times \vec{B}\), the direction of the force is given by the right-hand rule, which in this exercise results in a force perpendicular to the plane of the semicircular loop. Understanding the cross product's properties is vital for predicting the behavior of charged particles and current-carrying conductors in magnetic fields.
Polar Coordinates
Polar coordinates are a two-dimensional coordinate system where each point on a plane is defined by a distance from a reference point and an angle from a reference direction. This system is particularly useful when dealing with curves and shapes like the semicircle in our problem.

In the step-by-step solution, we observe how to parameterize the wire in polar coordinates: \(\vec{r}(\theta) = R \hat{r}(\theta)\), allowing the intuitive integration around the curve. By understanding polar coordinates, students can more easily integrate functions over circular paths and tackle complex geometries in physics and engineering problems.

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Most popular questions from this chapter

A charged particle moves under the influence of an electric field only. Is it possible for the particle to move with a constant speed? What if the electric field is replaced with a magnetic field?

In your laboratory, you set up an experiment with an electron gun that emits electrons with energy of \(7.50 \mathrm{keV}\) toward an atomic target. What deflection (magnitude and direction) will Earth's magnetic field \((0.300 \mathrm{G})\) produce in the beam of electrons if the beam is initially directed due east and covers a distance of \(1.00 \mathrm{~m}\) from the gun to the target? (Hint: First calculate the radius of curvature, and then determine how far away from a straight line the electron beam has deviated after \(1.00 \mathrm{~m} .)\)

Which of the following has the largest cyclotron frequency? a) an electron with speed \(v\) in a magnetic field with magnitude \(B\) b) an electron with speed \(2 v\) in a magnetic field with magnitude \(B\) c) an electron with speed \(v / 2\) in a magnetic field with magnitude \(B\) d) an electron with speed \(2 v\) in a magnetic field with magnitude \(B / 2\) e) an electron with speed \(v / 2\) in a magnetic field with magnitude \(2 B\)

A rail gun accelerates a projectile from rest by using the magnetic force on a current-carrying wire. The wire has radius \(r=5.10 \cdot 10^{-4} \mathrm{~m}\) and is made of copper having a density of \(\rho=8960 \mathrm{~kg} / \mathrm{m}^{3}\). The gun consists of rails of length \(L=1.00 \mathrm{~m}\) in a constant magnetic field of magnitude \(B=2.00 \mathrm{~T}\) oriented perpendicular to the plane defined by the rails. The wire forms an electrical connection across the rails at one end of the rails. When triggered, a current of \(1.00 \cdot 10^{4}\) A flows through the wire, which accelerates the wire along the rails. Calculate the final speed of the wire as it leaves the rails. (Neglect friction.)

A velocity selector is used in a mass spectrometer to produce a beam of charged particles with uniform velocity. Suppose the fields in a selector are given by \(\vec{E}=\left(2.207 \cdot 10^{4} \mathrm{~V} / \mathrm{m}\right) \hat{x}\) and \(\vec{B}=B_{y} \hat{y} .\) The speed with which charged particle can travel through the selector in the \(z\) -direction without being deflected is \(4.713 \cdot 10^{5} \mathrm{~m} / \mathrm{s}\). What is the value of \(B_{y} ?\)

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