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A proton, moving in negative \(y\) -direction in a magnetic field, experiences a force of magnitude \(F\), acting in the negative \(x\) -direction. a) What is the direction of the magnetic field producing this force? b) Does your answer change if the word "proton" in the statement is replaced by "electron"?

Short Answer

Expert verified
Answer: The direction of the magnetic field producing this force on both the proton and electron is in the positive z-direction.

Step by step solution

01

Apply the Right-Hand Rule for the Proton

To determine the direction of the magnetic field (B), we can use the right-hand rule related to the magnetic force experienced by a moving charged particle. The formula for the magnetic force experienced by a charged particle moving with velocity (v) in a magnetic field (B) is given by: F = q(v x B), where q is the charge of the particle and x denotes the cross product. Since the proton has a positive charge, we can use the right-hand rule as follows: 1. Point your thumb in the direction of the proton's velocity (negative y-direction). 2. Point your other fingers in the direction of the force (negative x-direction). 3. Your palm should face the direction of the required magnetic field. As you perform these steps, you should notice that the direction of the magnetic field is in the positive z-direction.
02

Determining the Direction of the Magnetic Field

By applying the right-hand rule as described in step 1, we can conclude that the direction of the magnetic field producing this force on the proton is in the positive z-direction. b) For this part, we need to find out if the direction of the magnetic field changes when the word "proton" in the statement is replaced by "electron".
03

Apply the Right-Hand Rule for the Electron

Since the electron has a negative charge, we need to adjust the application of the right-hand rule accordingly. We can do this by using the left-hand rule for negatively charged particles as follows: 1. Point your thumb in the direction of the electron's velocity (negative y-direction). 2. Point your other fingers in the direction of the force (negative x-direction). 3. Your palm should face the direction of the required magnetic field. As you perform these steps, you should notice that the direction of the magnetic field is in the positive z-direction.
04

Comparing the Directions of the Magnetic Fields

By applying the left-hand rule for the electron, we can conclude that the direction of the magnetic field producing this force on the electron is also in the positive z-direction. In conclusion, the answer does not change if the word "proton" in the statement is replaced by "electron". The direction of the magnetic field producing this force remains in the positive z-direction.

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Most popular questions from this chapter

An alpha particle \(\left(m=6.64 \cdot 10^{-27} \mathrm{~kg}, q=+2 e\right)\) is accelerated by a potential difference of \(2700 . \mathrm{V}\) and moves in a plane perpendicular to a constant magnetic field of magnitude \(0.340 \mathrm{~T}\), which curves the trajectory of the alpha particle. Determine the radius of curvature and the period of revolution.

Initially at rest, a small copper sphere with a mass of \(3.00 \cdot 10^{-6} \mathrm{~kg}\) and a charge of \(5.00 \cdot 10^{-4} \mathrm{C}\) is accelerated through a \(7000 .-\mathrm{V}\) potential difference before entering a magnetic field of magnitude \(4.00 \mathrm{~T}\), directed perpendicular to its velocity. What is the radius of curvature of the sphere's motion in the magnetic field?

In your laboratory, you set up an experiment with an electron gun that emits electrons with energy of \(7.50 \mathrm{keV}\) toward an atomic target. What deflection (magnitude and direction) will Earth's magnetic field \((0.300 \mathrm{G})\) produce in the beam of electrons if the beam is initially directed due east and covers a distance of \(1.00 \mathrm{~m}\) from the gun to the target? (Hint: First calculate the radius of curvature, and then determine how far away from a straight line the electron beam has deviated after \(1.00 \mathrm{~m} .)\)

A charged particle is moving in a constant magnetic field. Which of the following statements concerning the magnetic force exerted on the particle is (are) true? (Assume that the magnetic field is not parallel or antiparallel to the velocity.) a) It does no work on the particle. b) It may increase the speed of the particle. c) It may change the velocity of the particle. d) It can act only on the particle while the particle is in motion. e) It does not change the kinetic energy of the particle.

A charged particle moves under the influence of an electric field only. Is it possible for the particle to move with a constant speed? What if the electric field is replaced with a magnetic field?

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