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You are given two identical batteries and two pieces of wire, The red wire has a higher resistance than the black wire. You place the red wire across the terminals of one battery and the black wire across the terminals of the other battery, Which wire gets hotter?

Short Answer

Expert verified
Answer: The black wire with lower resistance gets hotter when connected to identical batteries.

Step by step solution

01

Understand Ohm's law and Power dissipation

Ohm's law states that the voltage (V) across a resistor is equal to the current (I) flowing through it multiplied by its resistance (R): V = IR. Furthermore, the power (P) dissipated by a resistor can be calculated as P = IV, which can also be expressed as P = I^2R or P = V^2/R depending on the known variables.
02

Compare power dissipation in both wires

In this case, we have two identical batteries, which means they have the same voltage (V). Since the red wire has higher resistance (R1) than the black wire (R2), we can use P = V^2/R to understand the power dissipation in each wire. For the red wire: P1 = V^2 / R1 For the black wire: P2 = V^2 / R2 As R1 > R2, the value of P1 < P2. This means that the power dissipation in the black wire is higher than in the red wire.
03

Determining which wire gets hotter

Power dissipation in a resistor (or wire) can be interpreted as the conversion of electrical energy into thermal energy, resulting in heating. Therefore, the wire dissipating more power will get hotter. From Step 2, we know that the black wire (lower resistance) has higher power dissipation than the red wire. Thus, the black wire gets hotter when connected to the battery terminals.

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Most popular questions from this chapter

You make a parallel connection between two resistors, resistor \(A\) having a very large resistance and resistor B having a very small resistance. The equivalent resistance for this combination will be a) slightly greater than the resistance of resistor A. b) slightly less than the resistance of resistor A. c) slightly greater than the resistance of resistor B. d) slightly less than the resistance of resistor B.

The most common material used for sandpaper, silicon carbide, is also widely used in electrical applications, One common device is a tubular resistor made of a special grade of silicon carbide called carborundum. A particular carborundum resistor (see the figure) consists of a thick-walled cylindrical shell (a pipe) of inner radius \(a=1.50 \mathrm{~cm},\) outer radius \(b=2.50 \mathrm{~cm},\) and length \(L=60.0 \mathrm{~cm}\). The resistance of this carborundum resistor at \(20.0^{\circ} \mathrm{C}\) is \(1.00 \mathrm{f}\). a) Calculate the resistivity of carborundum at room temperature, Compare this to the resistivities of the most commonly used conductors (copper, aluminum, and silver). b) Carborundum has a high temperature coefficient of resistivity: \(\alpha=2.14 \cdot 10^{-3} \mathrm{~K}^{-1}\). If, in a particular application, the carborundum resistor heats up to \(300 .{ }^{\circ} \mathrm{C}\), what is the percentage change in its resistance between room temperature \(\left(20.0^{\circ} \mathrm{C}\right)\) and this operating temperature?

Two conductors are made of the same material and have the same length \(L\). Conductor \(A\) is a hollow tube with inside diameter \(2.00 \mathrm{~mm}\) and outside diameter \(3.00 \mathrm{~mm}\); conductor \(\mathrm{B}\) is a solid wire with radius \(R_{\mathrm{B}}\). What value of \(R_{n}\) is required for the two conductors to have the same resistance measured between their ends?

Two resistors with resistances \(R_{1}\) and \(R_{2}\) are connected in parallel. Demonstrate that, no matter what the actual values of \(R_{1}\) and \(R_{2}\) are, the equivalent resistance is always less than the smaller of the two resistances,

Two cylindrical wires of identical length are made of copper and aluminum. If they carry the same current and have the same potential difference across their length, what is the ratio of their radii?

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