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What would be the consequence of setting the potential at \(+100 \mathrm{~V}\) at infinity, rather than taking it to be zero there? a) Nothing; the field and the potential would have the same values at every finite point. b) The electric potential would become infinite at every finite point, and the electric field could not be defined. c) The electric potential everywhere would be \(100 \mathrm{~V}\) higher, and the electric field would be the same. d) It would depend on the situation. For example, the potential due to a positive point charge would drop off more slowly with distance, so the magnitude of the electric field would be less.

Short Answer

Expert verified
Answer: The most plausible consequence would be that the electric potential everywhere would be 100 V higher, and the electric field would remain the same.

Step by step solution

01

Understanding electric potential at infinity

According to the convention, the reference point for the electric potential is taken to be at infinity, and its value is set to zero. This choice is arbitrary and helps simplify calculations. The idea behind this exercise is to evaluate whether the choice of a different value for the electric potential at infinity changes anything related to electric potential and field at finite distances.
02

Evaluating option a

A common notion is that the potential at infinity and how it is defined do not affect the potential difference between two points or the electric field at any point in the finite region. Therefore, one might think that there would be no difference in the values of the electric field and potential at every finite point, but we need to further analyze other options to make a conclusion.
03

Evaluating option b

Let's consider the case where the electric potential becomes infinite at every finite point. This would happen if we divide by a distance approaching zero. However, we are not changing the charge distribution or the distance between the charges. Thus, this option seems implausible because there's no reason why changing the reference value of the potential at infinity would result in the electric potential becoming infinite in every finite point and making the electric field undefined.
04

Evaluating option c

According to this option, increasing the potential at infinity by a constant value (+100 V) would result in an increase of the same constant value at every other point in space. This means the electric potential difference between any two points in space would remain the same, and since the electric field is related to the potential difference, the electric field would also be unchanged. This seems like a plausible explanation, but let's evaluate the last option before making a final conclusion.
05

Evaluating option d

This option suggests that the consequences depend on the specific situation. However, as stated earlier, how the electric potential is defined at infinity should not affect potential difference or the electric field at any point in the finite region as they are dependent upon the charge distribution and the distances involved. Therefore, it is unlikely that the answer would depend on the specific situation.
06

Final conclusion

After evaluating all four options, the most plausible consequence of setting the potential at \(+100 \mathrm{~V}\) at infinity rather than taking it to be zero there would be that the electric potential everywhere would be \(100 \mathrm{~V}\) higher (option c), and the electric field would be the same.

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Most popular questions from this chapter

A solid conducting sphere of radius \(R_{1}=1.435 \mathrm{~m}\) has a charge of Q evenly distributed over its surface. A second solid conducting sphere of radius \(R_{2}=0.6177 \mathrm{~m}\) is initially uncharged and at a distance of \(10.00 \mathrm{~m}\) from the first sphere. The two spheres are momentarily connected with a wire, which is then removed. The resulting charge on the second sphere is \(0.9356 \mu \mathrm{C}\). What was the original charge, \(Q\), on the first sphere?

A solid metal ball with a radius of \(3.00 \mathrm{~m}\) has a charge of \(4.00 \mathrm{mC}\) If the electric potential is zero far away from the ball, what is the electric potential at each of the following positions? a) at \(r=0 \mathrm{~m},\) the center of the ball b) at \(r=3.00 \mathrm{~m},\) on the surface of the ball c) at \(r=5.00 \mathrm{~m}\)

Consider an electron in the ground state of the hydrogen atom, separated from the proton by a distance of \(0.0529 \mathrm{nm} .\) a) Viewing the electron as a satellite orbiting the proton in the electric potential, calculate the speed of the electron in its orbit. b) Calculate an effective escape speed for the electron. c) Calculate the energy of an electron having this speed, and from it determine the energy that must be given to the electron to ionize the hydrogen atom.

Fully stripped (all electrons removed) sulfur \(\left({ }^{32} \mathrm{~S}\right)\) ions are accelerated from rest in an accelerator that uses a total voltage of \(1.00 \cdot 10^{9} \mathrm{~V}\). \({ }^{32} \mathrm{~S}\) has 16 protons and 16 neutrons. The accelerator produces a beam consisting of \(6.61 \cdot 10^{12}\) ions per second. This beam of ions is completely stopped in a beam dump. What is the total power the beam dump has to absorb?

Nuclear fusion reactions require that positively charged nuclei be brought into close proximity, against the electrostatic repulsion. As a simple example, suppose a proton is fired at a second, stationary proton from a large distance away. What kinetic energy must be given to the moving proton to get it to come within \(1.00 \cdot 10^{-15} \mathrm{~m}\) of the target? Assume that there is a head-on collision and that the target is fixed in place.

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