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When a positively charged rod is brought close to a neutral conductor without touching it, will the rod experience an attractive force, a repulsive force, or no force at all? Explain

Short Answer

Expert verified
Answer: A positively charged rod experiences an attractive force when it is brought close to a neutral conductor without touching it due to the process of electrostatic induction and the redistribution of charges within the conductor.

Step by step solution

01

Understand electrostatic induction

When a charged object is brought close to a neutral conductor but not touching it, the charges in the conductor redistribute because of the interaction between the charges. The negative charges in the conductor are attracted to the positively charged rod, while the positive charges are repelled but remain inside the conductor. This creates an electric polarization within the conductor.
02

Charge redistribution in the conductor

When the positively charged rod is brought close to the neutral conductor, the electrons, representing the negative charges, are attracted to the rod, accumulate on the surface of the conductor that's closer to the rod. The remaining positive charges (remain inside the conductor) will be on the surface that's farthest from the rod. This polarization establishes an electric field between the rod and the conductor.
03

Analyze the forces

Since opposite charges attract, the positively charged rod will experience an attractive force due to the accumulation of negative charges on the conductor's surface closer to it. The repulsion between the rod and the positive charges in the conductor is weaker as they are farther away from each other.
04

Conclude the explanation

Due to the electrostatic induction and charge redistribution within the neutral conductor, when a positively charged rod is brought close to it without touching, the rod experiences an attractive force from the conductor. This is because the accumulation of negative charges on the surface of the conductor closest to the rod exerts a stronger attractive force on the rod than the repulsive force from the positive charges farther away in the conductor.

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Most popular questions from this chapter

Two negative charges \((-q\) and \(-q)\) of equal magnitude are fixed at coordinates \((-d, 0)\) and \((d, 0)\). A positive charge of the same magnitude, \(q,\) and with mass \(m\) is placed at coordinate \((0,0),\) midway between the two negative charges. If the positive charge is moved a distance \(\delta \ll d\) in the positive \(y\) -direction and then released, the resulting motion will be that of a harmonic oscillator-the positive charge will oscillate between coordinates \((0, \delta)\) and \((0,-\delta) .\) Find the net force acting on the positive charge when it moves to \((0, \delta)\) and use the binomial expansion \((1+x)^{n}=1+n x,\) for \(x \ll 1,\) to find an expression for the frequency of the resulting oscillation. (Hint: Keep only terms that are linear in \(\delta .\) )

In general, astronomical objects are not exactly electrically neutral. Suppose the Earth and the Moon each carry a charge of \(-1.00 \cdot 10^{6} \mathrm{C}\) (this is approximately correct; a more precise value is identified in Chapter 22 ). a) Compare the resulting electrostatic repulsion with the gravitational attraction between the Moon and the Earth. Look up any necessary data. b) What effects does this electrostatic force have on the size, shape, and stability of the Moon's orbit around the Earth?

The Earth is constantly being bombarded by cosmic rays, which consist mostly of protons. These protons are incident on the Earth's atmosphere from all directions at a rate of \(1245 .\) protons per square meter per second. Assuming that the depth of Earth's atmosphere is \(120.0 \mathrm{~km}\), what is the total charge incident on the atmosphere in 5.000 min? Assume that the radius of the surface of the Earth is \(6378 . \mathrm{km}\).

Two identically charged particles separated by a distance of \(1.00 \mathrm{~m}\) repel each other with a force of \(1.00 \mathrm{~N}\). What is the magnitude of the charges?

If two charged particles (the charge on each is \(Q\) ) are separated by a distance \(d\), there is a force \(F\) between them. What is the force if the magnitude of each charge is doubled and the distance between them changes to \(2 d ?\)

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