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A Carnot engine takes an amount of heat \(Q_{H}=100 .\) J from a high- temperature reservoir at temperature \(T_{H}=1000 .{ }^{\circ} \mathrm{C},\) and exhausts the remaining heat into a low-temperature reservoir at \(T_{\mathrm{L}}=10.0^{\circ} \mathrm{C}\). Find the amount of work that is obtained from this process.

Short Answer

Expert verified
Answer: The amount of work obtained from the Carnot engine is 77.76 J.

Step by step solution

01

Convert the given temperatures to Kelvin

In order to work with the temperatures, we first need to convert them from Celsius to Kelvin: \(T_{H} = 1000^{\circ} C + 273.15 = 1273.15 K\) \(T_{L} = 10.0^{\circ}C + 273.15 = 283.15 K\)
02

Calculate the efficiency of the Carnot engine

Use the formula for the efficiency of a Carnot engine, which is: \(Efficiency = 1 - \frac{T_{L}}{T_{H}}\) Plug in the temperatures calculated in Step 1: \(Efficiency = 1 - \frac{283.15}{1273.15}\) \(Efficiency = 1 - 0.2224\) \(Efficiency = 0.7776\)
03

Calculate the work obtained from the Carnot engine

Now, use the efficiency and the provided amount of heat, \(Q_H\), to calculate the amount of work, \(W\), obtained from the Carnot engine: \(W = Efficiency \times Q_{H}\) \(W = 0.7776 \times 100\) \(W = 77.76 J\) Therefore, the amount of work obtained from the Carnot engine is \(77.76\) Joules.

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Most popular questions from this chapter

A heat pump has a coefficient of performance of \(5.00 .\) If the heat pump absorbs 40.0 cal of heat from the cold outdoors in each cycle, what is the amount of heat expelled to the warm indoors?

An inventor claims that he has created a water-driven engine with an efficiency of 0.200 that operates between thermal reservoirs at \(4.0^{\circ} \mathrm{C}\) and \(20.0^{\circ} \mathrm{C}\). Is this claim valid?

Consider a Carnot engine that works between thermal reservoirs with temperatures of \(1000.0 \mathrm{~K}\) and \(300.0 \mathrm{~K}\). The average power of the engine is \(1.00 \mathrm{~kJ}\) per cycle. a) What is the efficiency of this engine? b) How much energy is extracted from the warmer reservoir per cycle? c) How much energy is delivered to the cooler reservoir?

Suppose a person metabolizes \(2000 .\) kcal/day. a) With a core body temperature of \(37.0^{\circ} \mathrm{C}\) and an ambient temperature of \(20.0^{\circ} \mathrm{C}\), what is the maximum (Carnot) efficiency with which the person can perform work? b) If the person could work with that efficiency, at what rate, in watts, would he or she have to shed waste heat to the surroundings? c) With a skin area of \(1.50 \mathrm{~m}^{2},\) a skin temperature of \(27.0^{\circ} \mathrm{C}\), and an effective emissivity of \(e=0.600,\) at what net rate does this person radiate heat to the \(20.0^{\circ} \mathrm{C}\) surroundings? d) The rest of the waste heat must be removed by evaporating water, either as perspiration or from the lungs. At body temperature, the latent heat of vaporization of water is \(575 \mathrm{cal} / \mathrm{g}\). At what rate, in grams per hour, does this person lose water? e) Estimate the rate at which the person gains entropy. Assume that all the required evaporation of water takes place in the lungs, at the core body temperature of \(37.0^{\circ} \mathrm{C}\)

A heat engine operates with an efficiency of \(0.5 .\) What can the temperatures of the high-temperature and low-temperature reservoirs be? a) \(T_{\mathrm{H}}=600 \mathrm{~K}\) and \(T_{\mathrm{L}}=100 \mathrm{~K}\) b) \(T_{H}=600 \mathrm{~K}\) and \(T_{\mathrm{L}}=200 \mathrm{~K}\) c) \(T_{H}=500 \mathrm{~K}\) and \(T_{\mathrm{L}}=200 \mathrm{~K}\) d) \(T_{\mathrm{H}}=500 \mathrm{~K}\) and \(T_{\mathrm{L}}=300 \mathrm{~K}\) e) \(T_{\mathrm{H}}=600 \mathrm{~K}\) and \(T_{\mathrm{J}}=300 \mathrm{~K}\)

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