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A refrigerator operates by a) doing work to move heat from a low-temperature thermal reservoir to a high- temperature thermal reservoir. b) doing work to move heat from a high-temperature thermal reservoir to a low-temperature thermal reservoir. c) using thermal energy to produce useful work. d) moving heat from a low-temperature thermal reservoir to a hightemperature thermal reservoir without doing work. e) moving heat from a high-temperature thermal reservoir to a lowtemperature thermal reservoir without doing work.

Short Answer

Expert verified
Answer: A refrigerator operates by doing work to move heat from a low-temperature thermal reservoir (inside) to a high-temperature thermal reservoir (outside).

Step by step solution

01

Understanding the basic principles of refrigeration

A refrigerator is a heat engine that operates in a reversed cycle. Its main purpose is to transfer heat from a cold place (inside the refrigerator) to a warmer place (outside). The refrigerator does this by evaporation and condensation, using a refrigerant fluid which continuously moves through the system.
02

Analyzing each statement

Let's now analyze each of the provided statements: a) This statement says that the refrigerator does work to move heat from a low-temperature thermal reservoir to a high-temperature thermal reservoir. This matches the description of how a refrigerator functions since it takes the heat from the cold inside and releases it to the warmer outside. b) This statement says that the refrigerator does work to move heat from a high-temperature thermal reservoir to a low-temperature thermal reservoir. This is contrary to the refrigerator operation as it moves heat in the opposite direction. c) This statement says that the refrigerator uses thermal energy to produce useful work. A refrigerator uses work provided by an external source (like electricity) to move heat, not to produce work. d) This statement claims that the refrigerator moves heat from a low-temperature thermal reservoir to a high-temperature thermal reservoir without doing work. This is impossible based on the second law of thermodynamics. Work must be done to transfer heat from a colder to a warmer place. e) This statement claims that the refrigerator moves heat from a high-temperature thermal reservoir to a low-temperature thermal reservoir without doing work. This is also impossible based on the second law of thermodynamics, but it also contradicts the actual operation of a refrigerator as it moves heat from a cold place to a warm place.
03

Conclusion

Based on our analysis of each statement, we find that statement (a) is the correct description for how a refrigerator operates. A refrigerator does work to move heat from a low-temperature thermal reservoir (inside) to a high-temperature thermal reservoir (outside).

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Most popular questions from this chapter

Consider a Carnot engine that works between thermal reservoirs with temperatures of \(1000.0 \mathrm{~K}\) and \(300.0 \mathrm{~K}\). The average power of the engine is \(1.00 \mathrm{~kJ}\) per cycle. a) What is the efficiency of this engine? b) How much energy is extracted from the warmer reservoir per cycle? c) How much energy is delivered to the cooler reservoir?

A Carnot engine operates between a warmer reservoir at a temperature \(T_{1}\) and a cooler reservoir at a temperature \(T_{2}\). It is found that increasing the temperature of the warmer reservoir by a factor of 2 while keeping the same temperature for the cooler reservoir increases the efficiency of the Carnot engine by a factor of 2 as well. Find the efficiency of the engine and the ratio of the temperatures of the two reservoirs in their original form.

A Carnot engine takes an amount of heat \(Q_{H}=100 .\) J from a high- temperature reservoir at temperature \(T_{H}=1000 .{ }^{\circ} \mathrm{C},\) and exhausts the remaining heat into a low-temperature reservoir at \(T_{\mathrm{L}}=10.0^{\circ} \mathrm{C}\). Find the amount of work that is obtained from this process.

The burning of fuel transfers \(4.00 \cdot 10^{5} \mathrm{~W}\) of power into the engine of a \(2000 .-\mathrm{kg}\) vehicle. If the engine's efficiency is \(25.0 \%,\) determine the maximum speed the vehicle can achieve \(5.00 \mathrm{~s}\) after starting from rest.

An outboard motor for a boat is cooled by lake water at \(15.0^{\circ} \mathrm{C}\) and has a compression ratio of \(10.0 .\) Assume that the air is a diatomic gas. a) Calculate the efficiency of the engine's Otto cycle. b) Using your answer to part (a) and the fact that the efficiency of the Carnot cycle is greater than that of the Otto cycle, estimate the maximum temperature of the engine.

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