Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Can you think of a way to make a blackbody, a material that absorbs essentially all of the radiant energy falling on it, if you only have a material that reflects half the radiant energy that falls on it?

Short Answer

Expert verified
Explain your reasoning. Answer: No, it is not possible to create a blackbody using such a material. Although we can create a system where the radiant energy gets bounced around multiple times, the total energy absorbed eventually exceeds the initial incident energy, which is not physically possible. Hence, creating a blackbody using this particular material or any other similar methods is not feasible.

Step by step solution

01

Understand the properties of the given material

Given a material that reflects half of the radiant energy falling on it, this means the other half of the energy is absorbed.
02

Conceptualize an energy-absorbing system

To make the material absorb all the radiant energy falling on it, we can create a system where the reflected energy gets bounced around multiple times so that it is eventually absorbed. Imagine two parallel plates of the material, separated by a finite distance, with incident radiant energy falling on the first plate.
03

Calculate the energy absorbed in each bounce

When the radiant energy falls on the first plate, half of it will be absorbed and the other half will be reflected onto the second plate. At the second plate, half of the reflected energy will be absorbed, and the other half will be reflected back to the first plate. Similarly, half of the energy reflected back to the first plate will be absorbed and the rest will bounce back to the second plate. This bouncing and absorbing process will keep happening.
04

Model the absorption using a geometric series

To calculate the total energy absorbed by the system, we can represent this absorption with a geometric series: Total energy absorbed = (1/2)^1 + (1/2)^3 + (1/2)^5 + (1/2)^7 + ... Here (1/2)^n represents the fraction of energy absorbed at each reflection, where n is an odd positive integer.
05

Sum up the geometric series

To find the sum of this geometric series, we can use the formula for the sum of an infinite geometric series (since the bounces will continue indefinitely): Sum = a / (1 - r), where "a" is the first term of the series and "r" is the common ratio. In this case, a = (1/2)^1 and r = (1/2)^2. Sum = ((1/2)^1) / (1 - (1/2)^2) = (1/2) / (3/4) = 2/3.
06

Calculate the total energy absorbed

An important factor to consider is that the sum above only represents the absorption between the plates and not the initial absorption at the first plate. To find the total energy absorbed by the system, we should add the initial absorption to the sum we have calculated earlier. Initial energy absorbed = (1/2)^0 = 1. Total energy absorbed = Initial energy absorbed + Absorption between plates = 1 + 2/3 = 5/3. Since we have 5/3 > 1, this answer does not make any sense since total energy absorbed cannot be more than 100% of incident energy. This means our reasoning to create a blackbody using this material or any other similar methods would not be possible.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Radiant Energy Absorption
Radiant energy absorption is a fundamental concept in understanding how different materials interact with energy in the form of electromagnetic radiation, such as sunlight or heat. Most materials absorb some portion of this energy, which can cause them to heat up—an effect you might recognize when wearing dark clothing on a sunny day. This absorption depends on the material's properties; for example, a perfect blackbody is an idealized material that absorbs all incident radiant energy without reflecting any.

When we encounter a material that reflects half of the radiant energy, as in the exercise example, the remaining half is absorbed. However, achieving complete absorption (to simulate a blackbody) involves reducing the reflection repeatedly. This can be ingeniously done by placing the material in situations where it has multiple opportunities to absorb energy before that energy escapes, utilizing the concept of multiple reflections.
Geometric Series in Physics
In physics, a geometric series often appears when studying phenomena that involve repeated multiplications of a quantity, such as reflection and absorption of energy or the decay of a radioactive substance. The series consists of a sequence of terms each of which is multiplied by a constant ratio from the previous term.

In the context of the reflective material exercise, we can use a geometric series to model the absorption of energy over multiple reflections between two plates. Each term in the series represents the amount of energy absorbed in subsequent reflections, decreasing by a factor that's square of the fraction of energy reflected—since the energy is reflected twice before being re-absorbed. This modeling approach is powerful because it can predict the cumulative effect of a process repeated many times, which in other circumstances might be unintuitive or difficult to calculate.
Energy Reflection and Absorption
Energy reflection and absorption are two competing processes that determine the fate of radiant energy incident on a surface. Reflection is when energy bounces off a surface, while absorption is when the energy is taken in and converted, often to heat. The balance between these two processes can determine the efficiency of solar panels, the warming of buildings, and even the climate impact of Earth's surface.

The exercise imagines a scenario in which energy is repeatedly reflected between two surfaces, being partially absorbed with each reflection. This fictional setup reflects the intricacies of real-world systems where surfaces or materials can be engineered to optimize the absorption of radiant energy through multiple reflections. For efficient energy harnessing, a deep understanding of these dynamics is crucial, so studying reflection and absorption in tandem is an essential aspect of many technological and scientific endeavors.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A thermos bottle fitted with a piston is filled with a gas. Since the thermos bottle is well insulated, no heat can enter or leave it. The piston is pushed in, compressing the gas. a) What happens to the pressure of the gas? Does it increase, decrease, or stay the same? b) What happens to the temperature of the gas? Does it increase, decrease, or stay the same? c) Do any other properties of the gas change?

An exterior wall is \(5.869 \mathrm{~m}\) wide and \(3.289 \mathrm{~m}\) tall, and \(69.71 \mathrm{~W}\) of power is carried through it. The outdoor temperature is \(3.857{ }^{\circ} \mathrm{C},\) and the indoor temperature is \(24.21^{\circ} \mathrm{C} .\) What is the \(R\) factor of the material with which the wall is insulated?

A girl has discovered a very old U.S. silver dollar and is holding it tightly in her little hands. Suppose that she put the silver dollar on the wooden (insulating) surface of a table, and then a friend came in from outside and placed on top of the silver dollar an equally old penny that she just found in the snow, where it had been left all night. Estimate the final equilibrium temperature of the system of the two coins in thermal contact.

A copper sheet of thickness \(2.00 \mathrm{~mm}\) is bonded to a steel sheet of thickness \(1.00 \mathrm{~mm}\). The outside surface of the copper sheet is held at a temperature of \(100.0^{\circ} \mathrm{C}\) and the steel sheet at \(25.0^{\circ} \mathrm{C} .\) a) Determine the temperature of the copper-steel interface. b) How much heat is conducted through \(1.00 \mathrm{~m}^{2}\) of the combined sheets per second?

You become lost while hiking outside wearing only a bathing suit. a) Calculate the power radiated from your body, assuming that your body's surface area is about \(2.00 \mathrm{~m}^{2}\) and your skin temperature is about \(33.0^{\circ} \mathrm{C} .\) Also, assume that your body has an emissivity of \(1.00 .\) b) Calculate the net radiated power from your body when you are inside a shelter at \(20.0^{\circ} \mathrm{C} .\) c) Calculate the net radiated power from your body when your skin temperature dropped to \(27.0^{\circ} \mathrm{C}\)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free