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A thin aluminum rod of length \(L=2.00 \mathrm{~m}\) is clamped at its center. The speed of sound in aluminum is \(5000 . \mathrm{m} / \mathrm{s}\). Find the lowest resonance frequency for vibrations in this rod.

Short Answer

Expert verified
Answer: The lowest resonance frequency is 1250 Hz.

Step by step solution

01

Write down the given information and the formula to be used

We are given: - Length of the aluminum rod, \(L = 2.00 \mathrm{~m}\) - Speed of sound in aluminum, \(v = 5000 \mathrm{~m/s}\) We will use the formula for the fundamental frequency of a vibrating rod clamped at its center: \(f = \frac{v}{2L}\).
02

Substitute the given values

Now, let's substitute the given values into the formula: \(f = \frac{5000 \mathrm{~m/s}}{2 \times 2.00 \mathrm{~m}}\).
03

Simplify and calculate the lowest resonance frequency

Simplify and calculate the lowest resonance frequency: \(f = \frac{5000 \mathrm{~m/s}}{4.00 \mathrm{~m}} = 1250 \mathrm{~Hz}\). So, the lowest resonance frequency for vibrations in the given aluminum rod is 1250 Hz.

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Most popular questions from this chapter

Two vehicles carrying speakers that produce a tone of frequency \(1000.0 \mathrm{~Hz}\) are moving directly toward each other. Vehicle \(\mathrm{A}\) is moving at \(10.00 \mathrm{~m} / \mathrm{s}\) and vehicle \(\mathrm{B}\) is moving at \(20.00 \mathrm{~m} / \mathrm{s}\). Assume that the speed of sound in air is \(343.0 \mathrm{~m} / \mathrm{s},\) and find the frequencies that the driver of each vehicle hears.

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