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A sinusoidal transverse wave of wavelength \(20.0 \mathrm{~cm}\) and frequency 500\. Hz travels along a string in the positive \(z\) -direction. The wave oscillations take place in the \(x z\) -plane and have an amplitude of \(3.00 \mathrm{~cm}\). At time \(t=0,\) the displacement of the string at \(x=0\) is \(z=3.00 \mathrm{~cm}\) a) A photo of the wave is taken at \(t=0 .\) Make a simple sketch (including axes) of the string at this time. b) Determine the speed of the wave. c) Determine the wave's wave number. d) If the linear mass density of the string is \(30.0 \mathrm{~g} / \mathrm{m},\) what is the tension in the string? e) Determine the function \(D(z, t)\) that describes the displacement \(x\) that is produced in the string by this wave.

Short Answer

Expert verified
Answer: The displacement function for the given wave is D(z, t) = 0.03sin(31.4z - 1000πt + π/2).

Step by step solution

01

a) Sketch of the wave at t=0

At t=0, the displacement of the string at x=0 is z=3 cm, which means that the string is at its highest point since the amplitude of the wave is 3 cm. We have to sketch a sinusoidal wave in the xz-plane with its highest point at the origin (0, 3 cm) and wavelength 20 cm. Remember that the wave is moving in the positive z-direction, and oscillations are taking place in the xz-plane.
02

b) Determine the speed of the wave

To calculate the speed of the wave, we will use the formula: speed = frequency x wavelength v = fλ \\ v = (500 \ \mathrm{Hz})(0.2 \ \mathrm{m}) \\ v = 100 \ \mathrm{m/s} \\ So, the speed of the wave is 100 m/s.
03

c) Determine the wave's wave number

To calculate the wave number (k) we will use the formula: k = 2π/λ \\ k = \frac{2 \pi}{0.2 \ \mathrm{m}} \\ k \approx 31.4 \ \mathrm{m^{-1}} \\ The wave's wave number is approximately 31.4 m^{-1}.
04

d) Calculate the tension in the string

To find the tension in the string, we will use the formula: tension = linear density x speed^2 T = μv^2 \\ T = \left(\frac{30.0 \ \mathrm{g}}{\mathrm{m}} \times \frac{1 \ \mathrm{kg}}{1000\ \mathrm{g}}\right)(100 \ \mathrm{m/s})^2 \\ T \approx 300 \ \mathrm{N} \\ The tension in the string is approximately 300 N.
05

e) Determine the function D(z, t) that describes the displacement x.

We will use the general equation for a sinusoidal wave moving in the positive z-direction: D(z, t) = A sin(kz - ωt + φ) \\ Here, A is the amplitude (3 cm = 0.03 m), k is the wave number (31.4 m^{-1}), and ω is the angular frequency (2πf = 2π(500 Hz) = 1000π rad/s). At t=0, x=0 and z=3 cm = 0.03 m, which gives us: 0 = 0.03 \sin(0 - 0 + φ) \\ 0.03\ \mathrm{m} = 0.03 \sin φ \\ φ = \pi/2 \\ Now, we can put these values back into the general equation to obtain the displacement function: D(z, t) = 0.03 \sin(31.4z - 1000πt + π/2) \\ So, the displacement function D(z, t) is: D(z, t) = 0.03sin(31.4z - 1000πt + π/2).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wavelength
Wavelength (λ) is a key characteristic of a wave and is the distance between two consecutive points that are in phase. In simple terms, it's the length of one complete wave cycle, such as the distance from crest to crest or trough to trough in a transverse wave like the one described in the exercise. Wavelength is measured in meters (m) and directly affects the wave's speed and energy. Understanding wavelength is crucial for solving problems involving wave speed and frequency, as it's part of the fundamental relationship v = fλwhere v is the wave speed and f is the frequency.

Frequency
Frequency (f) of a wave refers to how many complete wave cycles pass a given point per second. It is measured in hertz (Hz), which is equivalent to 1/s. In our exercise, the frequency of the transverse wave is given as 500 Hz, meaning that 500 wavelengths pass a given point each second. The frequency is an essential component when determining other wave properties such as speed and energy, and it is inversely proportional to the wavelength, maintaining the relationship that higher frequencies result in shorter wavelengths and vice versa.

Wave Speed
Wave speed (v) is the rate at which the wave propagates through a medium. In the context of a transverse wave on a string, as in the exercise, the wave speed can be determined by multiplying its frequency (f) by its wavelength (λ), which is expressed by the equation v = fλ. For the wave in the exercise, the speed is calculated to be 100 m/s, indicating how fast the wave's energy and information are traveling along the string.

Wave Number
Wave number (k), not to be confused with wavelength, is a spatial frequency that describes the number of wave cycles in a unit distance. It's often used in the study of wave phenomena in physics and engineering. The formula to calculate wave number is given by k = 2π/λ, where λ is the wavelength. In our example, the computed wave number is approximately 31.4 m-1, which tells us how many cycles of the wave are present per meter of the wave's propagation along the z-axis.

Linear Mass Density
Linear mass density (μ) represents the mass per unit length of the string on which the wave is traveling and is usually expressed in kilograms per meter (kg/m). It is a critical factor when it comes to calculating the tension required to produce a certain wave speed in a string. The higher the linear mass density, the greater the tension needed to maintain the same wave speed. In the given problem, a linear mass density of 30.0 g/m translates to 0.03 kg/m, which was used to calculate the tension in the string responsible for the wave's propagation.

Tension in a String
Tension in a string is the force exerted along the string's length, and it plays a vital role in determining the wave speed on the string. For waves on a string, tension can be calculated using the equation T = μv^2 where T is the tension, μ is the linear mass density, and v is the wave speed. The exercise shows a practical application of this principle, where a tension of approximately 300 N is determined necessary to sustain a wave speed of 100 m/s on a string with the given mass density.

Sinusoidal Wave Equation
The sinusoidal wave equation is a mathematical description of a wave's displacement over time and position. It's given by the general form D(z, t) = A sin(kz - ωt + φ), where D(z, t) describes the displacement, A is the amplitude, k is the wave number, ω is the angular frequency, t is time, φ is the phase constant, and z is the position along the direction of wave propagation. This equation reflects the harmonic nature of sinusoidal waves and incorporates wave parameters like amplitude and frequency to detail how the wave evolves spatially and temporarily.

Using the given values in the exercise, including the determined phase constant of π/2, we derived a specific sinusoidal wave equation describing the transverse wave's motion on the string.

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Most popular questions from this chapter

A string is \(35.0 \mathrm{~cm}\) long and has a mass per unit length of \(5.51 \cdot 10^{-4} \mathrm{~kg} / \mathrm{m} .\) What tension must be applied to the string so that it vibrates at the fundamental frequency of \(660 . \mathrm{Hz?}\)

A guitar string with a mass of \(10.0 \mathrm{~g}\) is \(1.00 \mathrm{~m}\) long and attached to the guitar at two points separated by \(65.0 \mathrm{~cm}\). a) What is the frequency of the first harmonic of this string when it is placed under a tension of \(81.0 \mathrm{~N}\) ? b) If the guitar string is replaced by a heavier one that has a mass of \(16.0 \mathrm{~g}\) and is \(1.00 \mathrm{~m}\) long, what is the frequency of the replacement string's first harmonic?

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Students in a lab produce standing waves on stretched strings connected to vibration generators. One such wave is described by the wave function \(y(x, t)=(2.00 \mathrm{~cm}) \sin \left[\left(20.0 \mathrm{~m}^{-1}\right) x\right] \cos \left[\left(150 . \mathrm{s}^{-1}\right) t\right],\) where \(y\) is the transverse displacement of the string, \(x\) is the position along the string, and \(t\) is time. Rewrite this wave function in the form for a wave moving in the positive \(x\) -direction and a wave moving in the negative \(x\) -direction: \(y(x, t)=f(x-v t)+g(x+v t) ;\) that is, find the functions \(f\) and \(g\) and the speed, \(v\)

The speed of light waves in air is greater than the speed of sound waves in air by about a factor of a million. Given a sound wave and a light wave of the same wavelength, both traveling through air, which statement about their frequencies is true? a) The frequency of the sound wave will be about a million times greater than that of the light wave. b) The frequency of the sound wave will be about a thousand times greater than that of the light wave. c) The frequency of the light wave will be about a thousand times greater than that of the sound wave d) The frequency of the light wave will be about a million times greater than that of the sound wave. e) There is insufficient information to determine the relationship between the two frequencies.

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