Chapter 15: Problem 34
A particular steel guitar string has a mass per unit length of \(1.93 \mathrm{~g} / \mathrm{m}\). a) If the tension on this string is \(62.2 \mathrm{~N},\) what is the wave speed on the string? b) For the wave speed to be increased by \(1.00 \%\), how much should the tension be changed?
Short Answer
Expert verified
Answer: The tension should be changed by approximately 1.20 N.
Step by step solution
01
Recall the wave speed formula
The wave speed \(v\) on a string can be determined using the formula:
\(v = \sqrt{\frac{T}{\mu}}\)
where \(T\) is the tension on the string and \(\mu\) is the mass per unit length of the string.
02
Calculate the wave speed of the string
We are given the mass per unit length \(\mu = 1.93\ \text{g/m}\) and tension \(T = 62.2\ \text{N}\). To find the wave speed, we should first convert \(\mu\) to consistent units (kg/m):
\(\mu = 1.93\ \text{g/m} \cdot \frac{1\ \text{kg}}{1000\ \text{g}} = 0.00193\ \text{kg/m}\)
Now we plug the given values into the wave speed formula:
\(v = \sqrt{\frac{62.2\ \text{N}}{0.00193\ \text{kg/m}}} \approx 179.73\ \text{m/s}\)
So, the wave speed on the string is approximately \(179.73\ \text{m/s}\).
03
Calculate the desired increase in wave speed
We want to increase the wave speed by \(1.00\%\). To find the target wave speed, we can calculate:
\(v_{target} = v \cdot (1 + \frac{\Delta \%}{100}) = 179.73\ \text{m/s} \cdot 1.01 \approx 181.53\ \text{m/s}\)
The target wave speed is approximately \(181.53\ \text{m/s}\).
04
Determine the required tension for the target wave speed
To find the tension required to achieve the target wave speed, we can rearrange the wave speed formula for tension:
\(T_{target} = \mu \cdot v_{target}^2 = 0.00193\ \text{kg/m} \cdot (181.53\ \text{m/s})^2 \approx 63.40\ \text{N}\)
The required tension for the target wave speed is approximately \(63.40\ \text{N}\).
05
Calculate the required change in tension
Now we can calculate the required change in tension to achieve the target wave speed:
\(\Delta T = T_{target} - T = 63.40\ \text{N} - 62.2\ \text{N} \approx 1.20\ \text{N}\)
To achieve a \(1.00 \%\) increase in wave speed, the tension should be changed by approximately \(1.20\ \text{N}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Wave Speed Formula
Understanding the wave speed on a string is crucial for a variety of applications, from musical instruments to engineering designs. The speed at which a wave travels along a string, or its wave speed, is calculated using the wave speed formula:
\[ v = \sqrt{\frac{T}{\mu}} \]
In this formula, \( v \) represents the wave speed, \( T \) denotes the tension in the string, and \( \mu \) is the mass per unit length of the string. It's clear that wave speed increases with greater tension and decreases with increased mass per unit length. For instance, think of a guitar string; when you tighten the string (increase the tension), the pitch of the note (which corresponds to the wave speed) goes up.
\[ v = \sqrt{\frac{T}{\mu}} \]
In this formula, \( v \) represents the wave speed, \( T \) denotes the tension in the string, and \( \mu \) is the mass per unit length of the string. It's clear that wave speed increases with greater tension and decreases with increased mass per unit length. For instance, think of a guitar string; when you tighten the string (increase the tension), the pitch of the note (which corresponds to the wave speed) goes up.
- The tension \( T \) refers to the stretching force applied along the string.
- The mass per unit length \( \mu \) is how much mass is distributed along a unit of the string's length.
Tension in Strings
Tension is a force and is measured in newtons (N). It's important in the context of wave speed on a string because it is directly proportional to the wave speed squared. As the force causing the string to stretch, tension determines the medium's resistance to deformation and the restitution speed, which are crucial for wave propagation.
- High tension increases wave speed, producing higher-pitched sounds in musical strings.
- Low tension slows down wave speed, resulting in lower-pitched sounds.
Mass Per Unit Length
The mass per unit length, symbolized as \( \mu \), is pivotal to determining the wave speed on a string, as seen in the formula \( v = \sqrt{\frac{T}{\mu}} \). It represents the linear density or the amount of mass distributed along a single unit of the string's length and is expressed in kilograms per meter (kg/m).
- Thicker or denser strings, which have more mass per unit length, will produce waves that travel more slowly.
- Thinner or lighter strings result in faster wave propagation.