Chapter 15: Problem 22
Derive the expression for the energy of a wave \(E=\frac{1}{2} m \omega^{2} A^{2},\) where \(m\) is the mass of the substance that is oscillating, \(\omega\) is the angular velocity, and \(A(r)\) is the amplitude. Start by expressing the kinetic energy and potential energy of the wave, and then add these to get the energy of the wave.
Short Answer
Step by step solution
Key Concepts
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