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A hot-air balloon has a volume of \(2435 \mathrm{~m}^{3}\). The balloon can lift a weight of \(6194 \mathrm{~N}\) (including its own weight). The density of the air outside the balloon is \(1.205 \mathrm{~kg} / \mathrm{m}^{3}\). What is the density of the hot air inside the balloon?

Short Answer

Expert verified
Answer: The approximate density of the hot air inside the balloon is 0.9446 kg/m³.

Step by step solution

01

Understanding buoyant force

According to Archimedes' principle, the buoyant force acting on an object submerged in a fluid is equal to the weight of the fluid displaced by the object. In this case, the buoyant force acting on the hot-air balloon is equal to the difference in the weight of the air inside the balloon and the weight of the air it displaces.
02

Calculate the mass of the air displaced

To find the mass of the air displaced, we will use the given volume of the balloon and the density of the air outside the balloon. The formula for the mass is: Mass = Density * Volume Using the given values, Mass = 1.205 kg/m³ * 2435 m³ Mass ≈ 2934.175 kg
03

Calculate the weight of the air displaced

To calculate the weight of the air displaced, we will use the formula: Weight = Mass * Gravity Using the standard acceleration due to gravity (g = 9.81 m/s²), Weight ≈ 2934.175 kg * 9.81 m/s² Weight ≈ 28766.65775 N
04

Calculate the weight of the hot air inside the balloon

We know that the balloon can lift a total weight of 6194 N. Therefore, the weight of the hot air inside the balloon is equal to the difference between the weight of the air displaced and the weight it can lift: Weight of hot air = Weight of air displaced - Weight it can lift Weight of hot air ≈ 28766.65775 N - 6194 N Weight of hot air ≈ 22572.65775 N
05

Calculate the mass of the hot air inside the balloon

Now that we have the weight of the hot air inside the balloon, we can calculate its mass using the formula: Mass = Weight / Gravity Using the standard acceleration due to gravity (g = 9.81 m/s²), Mass ≈ 22572.65775 N / 9.81 m/s² Mass ≈ 2300.175 kg
06

Calculate the density of the hot air inside the balloon

Lastly, we will use the mass of the hot air inside the balloon and the volume of the balloon to calculate the density of the hot air. The formula for density is: Density = Mass / Volume Using the given volume of the balloon (2435 m³) and the calculated mass of the hot air, Density ≈ 2300.175 kg / 2435 m³ Density ≈ 0.9446 kg/m³ The density of the hot air inside the balloon is approximately 0.9446 kg/m³.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Archimedes' Principle
Archimedes' principle is a fundamental scientific concept that explains why objects like hot-air balloons are able to float in the air. The principle states that an object submerged in a fluid is buoyed up by a force that is equal to the weight of the fluid displaced by the object.

In practical terms, when a hot-air balloon is filled with hot air, it displaces a certain volume of the cooler, denser air surrounding it. The force pushing the balloon upwards—the buoyant force—is equal to the weight of this displaced air.

To solve a hot-air balloon problem using Archimedes' principle, we need to understand that if the balloon floats, the buoyant force must balance the weight of the balloon itself and the weight of the hot air inside. This concept is crucial when calculating how high a balloon can ascend or determining what density the hot air inside needs to be for the balloon to lift off.
Buoyant Force
The buoyant force comes into play as part of Archimedes' principle and is vital in solving problems related to hot-air balloons. It can be thought of as the fluid's pushback against the weight of the object submerged in it. For our hot-air balloon, the buoyant force must be equal to the balloon's weight if it is to hover at a constant altitude.

In the step-by-step solution for the hot-air balloon problem, you'll note that the buoyant force is the key force that allows the balloon to lift. It is the difference between the weight of the air displaced by the balloon and the weight of the hot air within it.

Understanding how to calculate this force is essential because it affects everything from the balloon's lift capacity to its stability in flight. To increase the balloon's altitude, you would need to decrease the density of the hot air inside it, effectively increasing the buoyant force.
Density Calculation
Density calculation is fundamental in understanding the physics behind hot-air balloons. The density of the air inside the balloon, compared to the air outside, dictates whether the balloon will sink, float, or rise.

Density is defined as mass per unit volume, expressed in the formula:
\( \text{Density} = \frac{\text{Mass}}{\text{Volume}} \). For a hot-air balloon, we are essentially comparing the density of the hot air inside the balloon (which is less dense due to heating and expansion) with the colder, denser air outside.

To calculate the density of the hot air, we need the mass of the air inside the balloon, which we derive from the weight (considering standard gravitational force) and the volume of the balloon, as shown in the steps of the solution. Recognizing how density affects the buoyant force and the balloon's lifting power is key. The lesser the density of the air inside the balloon, the greater the lift it can achieve.

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Most popular questions from this chapter

A water pipe narrows from a radius of \(r_{1}=5.00 \mathrm{~cm}\) to a radius of \(r_{2}=2.00 \mathrm{~cm} .\) If the speed of the water in the wider part of the pipe is \(2.00 \mathrm{~m} / \mathrm{s},\) what is the speed of the water in the narrower part?

Brass weights are used to weigh an aluminum object on an analytical balance. The weighing is done one time in dry air and another time in humid air. What should the mass of the object be to produce a noticeable difference in the balance readings, provided the balance's sensitivity is \(m_{0}=0.100 \mathrm{mg} ?\) (The density of aluminum is \(\rho_{\mathrm{A}}=2.70 \cdot 10^{3} \mathrm{~kg} / \mathrm{m}^{3}\); the density of brass is \(\rho_{11}=8.50 \cdot 10^{3} \mathrm{~kg} / \mathrm{m}^{3}\), The density of the dry air is \(1.2285 \mathrm{~kg} / \mathrm{m}^{3}\), and the density of the humid air is \(1.2273 \mathrm{~kg} / \mathrm{m}^{3}\).).

An approximately round tendon that has an average diameter of \(3.5 \mathrm{~mm}\) and is \(15 \mathrm{~cm}\) long is found to stretch \(0.37 \mathrm{~mm}\) when acted on by a force of \(13.4 \mathrm{~N}\). Calculate Young's modulus for the tendon.

In many problems involving application of Newton's Second Law to the motion of solid objects, friction is neglected for the sake of making the solution easier. The counterpart of friction between solids is viscosity of liquids. Do problems involving fluid flow become simpler if viscosity is neglected? Explain.

An airplane is moving through the air at a velocity \(v=200, \mathrm{~m} / \mathrm{s}\) Streamlines just over the top of the wing are compressed to \(80.0 \%\) of their original cross-sectional area, and those under the wing are not compressed at all. a) Determine the velocity of the air just over the wing. b) Find the difference in the pressure of the air just over the wing, \(P\), and that of the air under the wing, \(P\). The density of the air is \(1.30 \mathrm{~kg} / \mathrm{m}^{3}\). c) Find the net upward force on both wings due to the pressure difference, if the area of the wings is \(40.0 \mathrm{~m}^{2}\).

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