Chapter 2: Q56P (page 501)
You are exploring a newly discovered planet. The radius of the planet is \(7.20 \times {10^7}\;{\rm{m}}\). You suspend a lead weight from the lower end of a light string that is 4.00 m long and has mass 0.0280 kg. You measure that it takes 0.0685 s for a transverse pulse to travel the length of the string. The weight of the string is small enough that you ignore its effect on the tension in the string. Assuming that the mass of the planet is distributed with spherical symmetry, what is its mass?
Short Answer
Thus, the mass of the planet is \(29.53 \times {10^{25}}\;kg\).