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Two organ pipes, open at one end but closed at the other, are each 1.14m long. One is now lengthened by 2.00cm . Find the beat frequency that they produce when playing together in their fundamentals.

Short Answer

Expert verified

The beat frequency came out to be 1.3 Hz.

Step by step solution

01

Given Data

The length of the pipe is-1.14​ m

Increase in length- 2.00 cm

02

Formula of fundamental frequency

The formula of fundamental frequency is f=vλ.

As pipes are closed from the other end, λ=4L .

03

Calculate the beat frequency

Beat frequency can be expressed asf=v41L11L2 .

f=v411.14 m11.16 mf=344 m/s4×0.02 m1.14 m ×1.16 mf=1.3 Hz

So, the beat frequency is1.3 Hz .

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Most popular questions from this chapter

By touching a string lightly at its center while bowing, a violinist can produce a note exactly one octave above the note to which the string is tuned—that is, a note with exactly twice the frequency. Why is this possible?

The frequency of the note F4 is 349 Hz. (a) If an organ pipe is open at one end and closed at the other, what length must it have for its fundamental mode to produce this note at 20.0°C? (b) At what air temperature will the frequency be 370 Hz, corresponding to a rise in pitch from F to F-sharp? (Ignore the change in length of the pipe due to the temperature change.)

You have a stopped pipe of adjustable length close to a taut 62.0-cm, 7.25-g wire under a tension of 4110 N. You want to adjust the length of the pipe so that, when it produces sound at its fundamental frequency, this sound causes the wire to vibrate in its second overtone with very large amplitude. How long should the pipe be?

BIO Human Hearing. A fan at a rock concert is 30 m from the stage, and at this point the sound intensity level is 110 dB (a) How much energy is transferred to her eardrums each second? (b) How fast would a 2.0-mg mosquito have to fly (in mm/s) to have this much kinetic energy? Compare the mosquito’s speed with that found for the whisper in part (a) of Exercise 16.13.

The Vocal Tract. Many opera singers (and some pop singers) have a range of about21/2 octaves or even greater. Suppose a soprano’s range extends from A below middle C (frequency 220 Hz) up to E-flat above high C (frequency 1244 Hz). Although the vocal tract is quite complicated, we can model it as a resonating air column, like an organ pipe, that is open at the top and closed at the bottom. The column extends from the mouth down to the diaphragm in the chest cavity, and we can also assume that the lowest note is the fundamental. How long is this column of air if v = 354 m/s? Does your result seem reasonable, on the basis of observations of your own body?

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