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A Jaguar XK8 convertible has an eight-cylinder engine. At the beginning of its compression stroke, one of the cylinders contains499cm3of air at atmospheric pressure1.01*105Paand a temperature of27.0°C. At the end of the stroke, the air has been compressed to a volume of46.2cm3and the gauge pressure has increased to2.72*106Pa. Compute the final temperature.

Short Answer

Expert verified

The final temperature after compression is 475.23oC.

Step by step solution

01

The ideal gas equation and expression for final temperature

The ideal gas equation isPV=nRT.

The expression for temperature is thusT=PVnR where P is the pressure, V is the volume, T is the temperature, R is the universal gas constant = 8.314J/mol.K.

There exist two set of conditions , that of (P1,V1,T1) and (P2,V2,T2), then T1=P1V1nRand T2=P2V2nR. Combining which gives T1T2=P1V1nRP2V2nR.

Since the number of moles and R are constant,T1T2=P1V1P2V2 whereP1,V1 are the initial pressure and volume respectively, androle="math" localid="1668169464494" P2,V2 are the final pressure and volume respectively.

Then, expression for final temperature is derived from the above relation as T2=P2V2T1P1V1.

02

Calculating the value of final temperature

Substituting the values of P1=1.01*105Pa, V1=499cm3, T1=27oC=27+273K=300K, P2=2.72*106Pa,V2=46.2cm3 in T2=P2V2T1P1V1,

T2=2.7210646.2300.151.01105499T2=748.38KT2=(748.38273.15)CT2=475.23C

Thus, the final temperature after compression is 475.23C.

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