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The left end of a long glass rod 8.00 cm in diameter, with an index of refraction of 1.60, is ground and polished to a convex hemispherical surface with a radius of 4.00 cm. An object in the form of an arrow 1.50 mm tall, at right angles to the axis of the rod, is located on the axis 24.0 cm to the left of the vertex of the convex surface. Find the position and height of the image of the
arrow formed by paraxial rays incident on the convex surface. Is the image erect or inverted?

Short Answer

Expert verified

A. Image is formed at the a distance of 14.77cm

B. Height of the image is 0.577mm and it is inverted

Step by step solution

01

Important Concepts

The object image relationship for a spherical reflecting surface is

n1s+n2s'=n2-n1R

Wheren2 andn1 are the refraction index of the surfaces

s is th object distance from the vertex of the spherical surface and

s'is the image distance from the vertex of the spherical surface andR is the radius of curvature of the spherical surface

Magnification is given by

m=n1s'n2s

02

Find the object distance

Here we have

n2=1.6Forglassn1=1

The image is located at

It is negative since the image is on the opposite side of the outgoing light.

R=0.04m

Input this information in the formula

n1s+n2s'=n2-n1R10.24+1.6s'=1.6-10.04

Rearranging we have

s'=1.61.6-10.04-10.04s'=0.1477ms'=14.77cm

Hence, Image is formed at the a distance of 14.77cm

03

Find the magnification

Linear magnification is given by

m=-n1s'n2s=y'y

Where y'is the height of the image, and y is the height of the object

Rearrange to get

y'=-n1s'yn2sy'=-10.1477m0.00151.60.24m=-5.77mm

Hence,Height of the image is 0.577mm and it is inverted

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