Question

There appears to be anambiguity for the case s = 10cm to whether s′ is $\mathbf{s}\mathbf{\text{'}}\mathbf{=}\mathbf{+}\mathbf{\infty }$and$\mathbf{-}\mathbf{\infty }$whether the image is erect or inverted. How is this resolved? Or is it?

Short answer

Yes, both cases are hold.

Step-by-step solution

Definition of mirror

The term mirror may be defined as a special type of glass that used to see what behind you.

Explain reason of question

There is no image formed when s = f reflected rays and axis have angle zero degree. s > f in that case real image larger and farmer from the mirror. s' is larger and positive when $\mathrm{s}\to \mathrm{f}$. s < f in that case virtual image larger and farther from the mirror.is negative and magnitude larger when $\mathrm{s}\to \mathrm{f}$.

Hence, yes these both cases are hold.