Question

The following conversions occur frequently in physics and are very useful. (a) Use 1 mi = 5280 ft and 1 h = 3600 s to convert 60 mph to units of ft/s. (b) The acceleration of a freely falling object is 32 ft/s 2 . Use 1 ft = 30.48 cm to express this acceleration in units of m/s 2 . (c) The density of water is 1.0 g/cm3 . Convert this density to units of kg/m3

Short answer

The description is given below

Step-by-step solution

Step 1(Definition and basic conversion)

Conversion are basically used in physics to make the calculation easier or to keep all the units of quantities in one system.

Given-

1mile=1.6093km

1gallon=3.785L

(Calculation of Mileage)

We know that

So the mileage is

$$\begin{gathered} M=\frac{milesdriven}{gallonsusedtorefilthe\tan k} \\ M=\frac{51\times 1.6093}{3.7854}=21.7km/L \end{gathered}$$

So the answer is 21.7 km/L or 22km/L

Step3(Calculating amount of gas)

Let x be required amount of gas

So we have x=distance/mileage

$x=\frac{1490}{22.7}65.7L$

Step4(Calculating number of tank for 65.7 L gas)

The number of tank is given by=x /amount of gas in 1 tank

So, we have no of tanks =65.7/44=1.5

So the answer is 1.5 or 1.49 or 1

Step 5(Conclusion)

Mileage of vehicle=22Km/L

Amount of gas =65.7L

Number of tank for gas= 1