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Chapter 1: Q2DQ (page 389)

A rubber hose is attached to a funnel, and the free end is bent around to point upward. When water is poured into the funnel, it rises in the hose to the same level as in the funnel, even though the funnel has a lot more water in it than the hose does. Why? What supports the extra weight of the water in the funnel?

Short Answer

Expert verified

The height of the water will be similar in the hose as in the funnel.

Step by step solution

01

Understanding the Bernoulli’s principle

In this problem, the concept of Bernoulli’s principle will be used in order to estimate the height of the water in the hose and the funnel.

02

Evaluating the height of the water

The relation from Bernoulli’s principle is given by,

In the above relation, it is observed that the pressure of the water doesn’t rely on the cross-sectional area of the pipes. It is dependent on the height of the water level. Water in the hose, as well as the funnel, is exposed to similar atmospheric pressure. Hence the rise of the water in the hose will be at the same level as in the funnel. Also, the reaction forces from the side of the funnel will support the extra weight of the water present in the funnel.

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Most popular questions from this chapter

Water flows steadily from an open tank as in Fig. P12.81. The elevation of point 1 is 10.0 m, and the elevation of points 2 and 3 is 2.00 m. The cross-sectional area at point 2 is 0.0480 m2; at point 3 it is 0.0160 m2. The area of the tank is very large compared with the cross-sectional area of the pipe. Assuming that Bernoulli’s equation applies, compute (a) the discharge rate in cubic meters per second and (b) the gauge pressure at point 2.

The driver of a car wishes to pass a truck that is traveling at a constant speed of20.0m/s(about41mil/h). Initially, the car is also traveling at20.0m/s, and its front bumper is24.0mbehind the truck’s rear bumper. The car accelerates at a constant 0.600m/s2, then pulls back into the truck’s lane when the rear of the car is26.0mahead of the front of the truck. The car islong, and the truck is 21.0m long. (a) How much time is required for the car to pass the truck? (b) What distance does the car travel during this time? (c) What is the final speed of the car?

Starting from the front door of a ranch house, you walk 60.0 m due east to a windmill, turn around, and then slowly walk 40.0 m west to a bench, where you sit and watch the sunrise. It takes you 28.0 s to walk from the house to the windmill and then 36.0 s to walk from the windmill to the bench. For the entire trip from the front door to the bench, what are your (a) average velocity and (b) average speed?

A closed and elevated vertical cylindrical tank with diameter 2.00 m contains water to a depth of 0.800 m. A worker accidently pokes a circular hole with diameter 0.0200 m in the bottom of the tank. As the water drains from the tank, compressed air above the water in the tank maintains a gauge pressure of 5 X 103Pa at the surface of the water. Ignore any effects of viscosity. (a) Just after the hole is made, what is the speed of the water as it emerges from the hole? What is the ratio of this speed to the efflux speed if the top of the tank is open to the air? (b) How much time does it take for all the water to drain from the tank? What is the ratio of this time to the time it takes for the tank to drain if the top of the tank is open to the air?

In each case, find the x- and y-components of vectorA→: (a)A→=5.0i^-6.3j^; (b)A→=11.2j^-9.91i^; (c)A→=-15.0i^+22.4j^; (d)A→=5.0B→, whereB→=4i^-6j^.
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