Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A spring of negligible mass has force constant k = 1600 N/m. (a) How far must the spring be compressed for 3.20 J of potential energy to be stored in it? (b) You place the spring vertically with one end on the floor. You then drop a 1.20-kg book onto it from a height of 0.800 m above the top of the spring. Find the maximum distance the spring will be compressed.

Short Answer

Expert verified

(a) The compression of spring is 0.063 m

(b) The maximum compressed distance for spring due to book is 0.11 m .

Step by step solution

01

Given Data:

The force constant of the spring is k = 1600 N/m

The potential energy for spring compression is U = 3.20 J

The mass of the book is m = 1.20 m

The height of the book is h = 0.800 m

02

Define Potential energy:

The energy stored due to the variation in the position with some reference position is the potential energy. The potential energy is used to calculate the compression of the spring.

03

(a) Determine the tension in the rope by using vertical equilibrium

The compression of the spring is calculated as:

U=12kx2

Here, U is the potential energy of spring, x is the compression, and k is the force constant of spring.

Substitute all the values in the above equation and we get,

3.20J=121600N/mx2x=0.063m

Therefore, the compression of spring is 0.063 m .

04

(b) Determine the maximum distance of compression due to the book

The maximum compressed distance is calculated as:

mgh=12ky2

Here, m is the mass of the book, g is the gravitational acceleration, h the height dropped by the book, k is the force constant, and y is compression of spring.

Substitute all the values in the above equation, and we get,

1.20kg9.80.800m=121600N/my2y=0.11m

Therefore, the maximum compressed distance for spring due to the book is 0.11 m .

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Comparing Example 12.1 (Section 12.1) and Example 12.2 (Section 12.2), it seems that 700 N of air is exerting a downward force of 2.0×106Non the floor. How is this possible?

You decide to visit Santa Claus at the north pole to put in a good word about your splendid behavior throughout the year. While there, you notice that the elf Sneezy, when hanging from a rope, produces a tension of 395.0Nin the rope. If Sneezy hangs from a similar rope while delivering presents at the earth’s equator, what will the tension in it be? (Recall that the earth is rotating about an axis through its north and south poles.) Consult Appendix F and start with a free-body diagram of Sneezy at the equator.

For the hydraulic lift shown in Fig. 12.7, what must be the ratio of the diameter of the vessel at the car to the diameter of the vessel where the force F1 is applied so that a 1520-kg car can be lifted with a force F1 of just 125 N?

A car is stopped at a traffic light. It then travels along a straight road such that its distance from the light is given byxt=bt2-ct3, whereb=2.40m/s2andc=0.120m/s3. (a) Calculate the average velocity of the car for the time interval t = 0 to t = 10.0 s. (b) Calculate the instantaneous velocity of the car at t = 0, t = 5.0 s, and t = 10.0 s. (c) How long after starting from rest is the car again at rest?

How many times does a human heart beat during a person’s lifetime? How many gallons of blood does it pump? (Estimate that the heart pumps 50 cm3 of blood with each beat.)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free