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For the circuit shown in Fig. E26.7 find the reading of the idealized ammeter if the battery has an internal resistance of 3.26 Ω.

Short Answer

Expert verified

The reading of the idealized ammeter is 0.769 A.

Step by step solution

01

Given Data

Let R1 = 45.0 Ω, R2 = 18.0 Ω and R3 = 15.0 Ω. The internal resistance of the battery is r=3.26 Ω

02

Calculation for the equivalent Resistance

The two resistors R1 and R3 are in parallel and calculating their combination by resistors in a parallel equation as:

R13=R1R3R1+R3

Substitute values to get R13 as:

R13=R1R3R1+R3=45.0Ω15.0Ω45.0Ω+15.0Ω=11.25Ω

03

Calculation of the current

R13 is in series with R2 so the current is the same for both of them which also equals the current flows in all circuits. The battery has an internal resistance and the emf of the battery isε= 25.0 Vso the current flows in the circuit could be calculated by Ohm's law in the form as:

l=εRt

where Rt is the total resistance in the circuit = R13+ R2+ r.

Substitute values to get the current that reads by the ammeter

l=εR13+R2+r=ε11.25Ω+18.0Ω+3.26Ω=0.796A

Therefore, the reading of the ammeter is 0.769 A.

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