Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A particle with charge 7.26 * 10-8 C is moving in a region where there is a uniform 0.650-T magnetic field in the +x-direction. At a particular instant, the velocity of the particle has components vx = -1.68 * 104 m/s, vy = -3.11 * 104 m/s, and vz = 5.85 * 104 m/s. What are the components of the force on the particle at this time?

Short Answer

Expert verified

The force components areFx=0,Fy=2.76×103N,Fz=1.47×103N

Step by step solution

01

Magnetic force

The magnetic force is given by

FB=q(v×B)

02

Determine the magnetic force components acting on that particle

The magnetic force acting on a charged particle is

FB=q(v×B)

Therefore,

F=qv×B=qi^j^k^vxvyvzBxByBz

Therefore, the components of the force are

Fx=q(vyBzvzBy)=0AndFy=q(vzBxvxBz)=qvzBx=(7.26×108C)(5.85×104m/s)(0.650T)=2.76×103N

And,

Fz=q(vxByvyBx)=qvyBx=(7.26×108C)(3.11×104m/s)(0.650T)=1.47×103N

Therefore, the force components areFx=0,Fy=2.76×103N,Fz=1.47×103N

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free