Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

You have a pure (24-karat) gold ring of mass 10.8 g. Gold has an atomic mass of 197 g/mol and an atomic number of 79. (a) How many protons are in the ring, and what is their total positive charge? (b) If the ring carries no net charge, how many electrons are in it?

Short Answer

Expert verified
  1. The total number and charge of protons in the ring are 2.61×10244.18×105Crespectively.
  2. The number of electrons in the ring when there is no charge is2.61×1024electrons.

Step by step solution

01

(a) Determination of the total number and charge of protons in the ring.

The number atoms in 1 mole of a substance are the Avogadro number NA.

So, the number of lead atoms is,

N=nNA

Here, n is the number of moles and NA is the Avogadro Number.

Now,the atomic mass of lead is,

M = 197g/mol

So the number of atoms in a mass of m = 10.8 is,

N=6.022×1023atoms/mol10.8g197g/mol=3.300×1022atoms

Atomic number is 79, thus the number of protons is,

np=(79protons/atom)3.300×1022atoms=2.61×1024protons.

Thus,Charge of the protons is,

Q=np1.60×1019C/proton=4.18×105C

02

(b) Determination of the number of electrons in the ring when there is no charge.

The number of electrons is always equal to the number of protons. So,

ne=np=2.61×1024electrons

Thus, the number of electron son the ring is 2.61×1024electrons .

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The tightly wound toroidal solenoid is one of the few configurations for which it is easy to calculate self-inductance. What features of the toroidal solenoid give it this simplicity?

An electron experiences a magnetic force of magnitude4.60×10-15Nwhen moving at an angle of 60.0° with respect toa magnetic field of magnitude3.50×10-3T. Find the speed ofthe electron.

A 12.4-µF capacitor is connected through a 0.895-MΩ resistor to a constant potential difference of 60.0 V. (a) Compute the charge on the capacitor at the following times after the connections are made: 0, 5.0 s, 10.0 s, 20.0 s, and 100.0 s. (b) Compute the charging currents at the same instants. (c) Graph the results of parts (a) and (b) for t between 0 and 20 s

In the circuit shown in Fig. E26.49, C = 5.90 mF, Ԑ = 28.0 V, and the emf has negligible resistance. Initially, the capacitor is uncharged and the switch S is in position 1. The switch is then moved to position 2 so that the capacitor begins to charge. (a) What will be the charge on the capacitor a long time after S is moved to position 2? (b) After S has been in position 2 for 3.00 ms, the charge on the capacitor is measured to be 110 mC What is the value of the resistance R? (c) How long after S is moved to position 2 will the charge on the capacitor be equal to 99.0% of the final value found in part (a)?

An idealized voltmeter is connected across the terminals of a15.0-Vbattery, and arole="math" localid="1655719696009" 75.0-Ω appliance is also connected across its terminals. If the voltmeter reads11.9V (a) how much power is being dissipated by the appliance, and (b) what is the internal resistance of the battery?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free