Question

A 18.0mF capacitor is placed across a 22.5-V battery for several seconds and is then connected across a 12.0-mH inductor that has no appreciable resistance. Sketch graphs of the charge on the capacitor plates and the current through the inductor as functions of time.

Short answer

The charge on a capacitor in LC circuit varies as function of$\mathrm{cosine}$.

Here, The charge on capacitor is given by $Q=Q_0\cos \omega t$

The current passing through the inductor varies as function of $\mathrm{sine}$.

Here, The current passing through the inductor is given by $l=\left|-l_0\sin \omega t\right|$

Step-by-step solution

Graphical behaviour of charge of on capacitor and current passing through the inductor.

The charge on a capacitor in LC circuit varies as function of$\mathrm{cosine}$.

Here, The charge on capacitor is given by $Q=Q_0\cos \omega t$

The current passing through the inductor varies as function of $\mathrm{sine}$.

Here, The current passing through the inductor is given by $l=\left|-l_0\sin \omega t\right|$

Step 2: The graphs of of the charge on the capacitor plates

The graph of current through the inductor as functions of time.