Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

An electromagnetic standing wave in air has frequency 75.0 MHz. What is the distance between a nodal plane of Eand the closest nodal plane of B?

Short Answer

Expert verified

The distance between a nodal plane of Eand the closest nodal plane of Bis 1m.

Step by step solution

01

Step 1: The standing EM wave

The EM waves can form standing waves when EM waves are reflected from the end of a transmission line.

The wavelength of standing wave produced due to a nodal plane of Eand nodal plane ofB

The wavelength of standing wave is produced due to a nodal plane of Eand nodal plane of Bis given by

role="math" localid="1664426475142" x=λ4

Where, xis the distance between two nodal planes and λis the wavelength of wave.

Speed of propagating wave

The speed of propagating wave is given by

v=

Where, vis the speed of propagation of wave and role="math" localid="1664426617586" fis the frequency of wave.

02

The calculation of wavelength of wave

Given: f=75MHz=75×106Hz,v=3×108m/s,

Using

v=

Put the values of constants in above equation

3×108ms-1=75×106Hz×λλ=3×10875×106λ=4m

Thus, the wavelength of wave is 4m

03

The calculation of nodal plane of E→ and closest nodal plane of  B→

Using

x=λ4

Now, put the value of wavelength in above equation

x=4m4x=1m

Thus, the distance between a nodal plane of Eand the closest nodal plane oflocalid="1664427274713" Bis localid="1664427133460" 1m.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free