Question

For the system of capacitors shown in Fig. E24.21, a potential difference of 25 V is maintained across ab.

(a) What is the equivalent capacitance of this system between a and b?

(b) How much charge is stored by this system?

(c) How much charge does the 6.5-nF capacitor store?

(d) What is the potential difference across the 7.5-nF capacitor?

Short answer

The equivalent capacitance for the system is 19.29nF

The net charge stored in the system is 482.35nC

The charge is stored across the 6.5nF register is 162.5nC

The potential difference across terminals (a,b) is 25Vb

Step-by-step solution

Step 1:

Given capacitors as shown in the figure.

The equivalent equation for the three capacitors in the middle

To get the equivalent capacitance for the system we add the three capacitance

Step 2:

b) The net charge is

Step 3:

C) The charge is stored across the 6.5nF register.

Step 4:

The potential difference across terminals (a,b) is same as they are connected in parallel.