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You apply a potential difference of 4.50 Vbetween the ends of a wire that is 2.50 m in length and 0.654 mm in radius. The resulting current through the wire is 17.6 A. What is the resistivity of the wire?

Short Answer

Expert verified

The resistivity of the wire is13.8×10-8Ωm .

Step by step solution

01

Determine the area of the wire

The given data is:

V=4.50V,L=2.50,m=0.654mm,andl=17.6A

Now, the area of the wire can be calculated as:

A=πr2A=π×0.654×10-32A=1.344×10-6m2

02

Determine the resistance of the wire

Now,

R=VIR=4.5017.6R=0.256Ω

Thus, the resistance of the wire is 0.256Ω

03

Determine the resistivity of the wire

The formula to find resistivity is:

ρ=RAL

Substitute the given values

ρ=0.256Ω1.344×10-6m22.50mρ=13.8×10-8Ωm

Therefore, the resistivity of the wire is 13.8×10-8Ωm.

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