Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

If you peel two strips of transparent tape off the same roll and immediately let them hang near each other, they will repel each other. If you then stick the sticky side of one to the shiny side of the other and rip them apart, they will attract each other. Give a plausible explanation, involving transfer of electrons between the strips of tape, for this sequence of events.

Short Answer

Expert verified

The transfer of electrons causes the strips to undergo attraction.

Step by step solution

01

Concept of electric charge.

An electric charge is an entity or a property of a particle that causes it to get influenced via experiencing a force when placed inside an electric or magnetic field.The charge due to electrons is mainly what is referred to as electric charge and one electron carries a charge of 1.6x10-19C. Like charges repel each other and unlike charges attract each other

02

Explanation of transfer of electrons and the sequence of events.

When the two strips are peeled, the negatively charged electrons flow to the rest of the tape roll from the stripped part. So, the tapes that are stripped are both negatively charged at the same time on their sticky side and will repel for sure. Now, if the sticky side of one is pasted on the shiny side of the other and then stripped off forcefully separating them in the process, then there will be a flow of electrons again. But this time there will be a net positive charge build-up which will cause the attraction between the two strips. Thus, the transfer of negative charge from one strip to other causes one to be positive and then subsequent attraction.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The circuit shown in Fig. E25.33 contains two batteries, each with an emf and an internal resistance, and two resistors. Find (a) the current in the circuit (magnitude and direction) and (b) the terminal voltage Vabof the 16.0-V battery.

Fig. E25.33

High-voltage power supplies are sometimes designed intentionally to have rather large internal resistance as a safety precaution. Why is such a power supply with a large internal resistance safer than a supply with the same voltage but lower internal resistance?

(See Discussion Question Q25.14.) Will a light bulb glow more brightly when it is connected to a battery as shown in Fig. Q25.16a, in which an ideal ammeter is placed in the circuit, or when it is connected as shown in Fig. 25.16b, in which an ideal voltmeter V is placed in the circuit? Explain your reasoning.

Cyclotrons are widely used in nuclear medicine for producing short-lived radioactive isotopes. These cyclotrons typically accelerate H-(the hydride ion, which has one proton and two electrons) to an energy of 5MeVto20MeV.This ion has a mass very close to that of a proton because the electron mass is negligible about 12000of the proton’s mass. A typical magnetic field in such cyclotrons is 1.9T..(a) What is the speed of a 5.0-MeVH-? (b) If the H-has energy 5.0MeVandB=1.9T what is the radius of this ion’s circulator orbit?

An electron experiences a magnetic force of magnitude4.60×10-15Nwhen moving at an angle of 60.0° with respect toa magnetic field of magnitude3.50×10-3T. Find the speed ofthe electron.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free