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A student asked, “Since electrical potential is always proportional to potential energy, why bother with the concept of potential at all?” How would you respond?

Short Answer

Expert verified

The electric field is a conservative field and depending on the electrical potential- As We know to calculate the electric potential needs at least two charges one of them is a test charge. If We put a test charge in a medium of many charges, then the electric field generates around the test charge due to the surrounding charges.

Step by step solution

01

About electric potential 

The electric potential difference between points A and B, VB−VA is defined to be the change in potential energy of a charge q moved from A to B, divided by the charge.Units of potential difference are joules per coulomb, given the name volt (V) after Alessandro Volta.

02

Determine the potential

Solution:

As we know the electric field is a conservative field- Also, We know that the electric field is given by the following relation:

As we know in mechanics in general, We have two important concepts energy and potentiaL As We mention the electric field is a conservative field and depending on the electrical potentiaL As We know to calculate the electric potential needs at least two charges one of them is a test charge- If we put a test charge in a medium of many charges, then the electric filed generates around the test charge due to the surrounding charges- In general, We have electric potential and mechanical potential-

Therefore

The electric field is a conservative field and depending on the electrical potential- As We know to calculate the electric potential needs at least two charges one of them is a test charge. If We put a test charge in a medium of many charges, then the electric field generates around the test charge due to the surrounding charges.

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Most popular questions from this chapter

You want to produce three 1.00-mm-diameter cylindrical wires,

each with a resistance of 1.00 Ω at room temperature. One wire is gold, one

is copper, and one is aluminum. Refer to Table 25.1 for the resistivity

values. (a) What will be the length of each wire? (b) Gold has a density of1.93×10-4kgm3.

What will be the mass of the gold wire? If you consider the current price of gold, is

this wire very expensive?

An open plastic soda bottle with an opening diameter of 2.5cmis placed on a table. A uniform 1.75-Tmagnetic field directed upward and oriented25° from the vertical encompasses the bottle. What is the total magnetic flux through the plastic of the soda bottle?

Questions: When a thunderstorm is approaching, sailors at sea sometimes observe a phenomenon called “St. Elmo’s fire,” a bluish flickering light at the tips of masts. What causes this? Why does it occur at the tips of masts? Why is the effect most pronounced when the masts are wet? (Hint: Seawater is a good conductor of electricity.)

In the circuit shown in Fig. E25.30, the 16.0-V battery is removed and reinserted with the opposite polarity, so that its negative terminal is now next to point a. Find (a) the current in the circuit (magnitude anddirection); (b) the terminal voltage Vbaof the 16.0-V battery; (c) the potential difference Vacof point awith respect to point c. (d) Graph the potential rises and drops in this circuit (see Fig. 25.20).

The definition of resistivity (ρ=EJ) implies that an electrical field exist inside a conductor. Yet we saw that in chapter 21 there can be no electrostatic electric field inside a conductor. Is there can be contradiction here? Explain.

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