We are givenandare connected in parallel where =3.00 uF and = 5.00 pF and the potential between a and b is = 520 V
(a) In Figure 24.9a, the two capacitors are connected in parallel. As shown in the
figure the upper plates of the two capacitors are connected by conducting wires
to form an equipotential surface, and the lower plates form another. Therefore, in a
parallel connection, the potential difference for all individual capacitors is the
same and is equal to
So we can get the charge for each capacitor by using the value of the given
potential and the capacitance of each capacitor as next
For the first capacitor , the chargeis given by
For the second capacitor , the chargeis given by