Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

In household wiring, copper wire 2.05 mm in diameter is often used. Find the resistance of a 24.0-m length of this wire.

Short Answer

Expert verified

Resistance of wireR=0.125Ω

Step by step solution

01

Step 1:

Given data:

d=2.05mm=2.05×10-3mL=24.0m

The cross-section of the area of the wire is:

A=π4d2=π4×2.05×10-3m2=3.3×10-6m2

As the copper resistivity isρ=1.72×10-8Ω.m

Putting the value of ρ, now the resistance is:

R=ρLA=1,72×10-8Ω.m24.0m3.3×10-6m2=0.125Ω

Hence, the Resistance of a wire isR=0.125Ω

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The magnetic force on a moving charged particle is always perpendicular to the magnetic fieldB. Is the trajectory of a moving charged particle always perpendicular to the magnetic field lines? Explain your reasoning.

CALC The region between two concentric conducting spheres with radii and is filled with a conducting material with resistivity ρ. (a) Show that the resistance between the spheres is given by

R=ρ4π(1a-1b)

(b) Derive an expression for the current density as a function of radius, in terms of the potential differenceVab between the spheres. (c) Show that the result in part (a) reduces to Eq. (25.10) when the separation L=b-abetween the spheres is small.

Why does an electric light bulb nearly always burn out just as you turn on the light, almost never while the light is shining?

A 1.50-mcylindrical rod of diameter 0.500cmis connected to

a power supply that maintains a constant potential difference of 15.0Vacross

its ends, while an ammeter measures the current through it. You observe that

at room temperature (20.0C)the ammeter reads 18.5Awhile at 92.0Cit

reads 17.2A. You can ignore any thermal expansion of the rod. Find (a) the

resistivity at and (b) the temperature coefficient of resistivity at for the material of the rod.

A horizontal rectangular surface has dimensions 2.80cmby 3.20cmand is in a uniform magnetic field that is directed at an angle of 30.0°above the horizontal. What must the magnitude of the magnetic field be to produce a flux of 3.10×10-4Wb through the surface?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free